Submission #1273177

#TimeUsernameProblemLanguageResultExecution timeMemory
1273177hiepsimauhongCurtains (NOI23_curtains)C++20
100 / 100
686 ms63536 KiB
#include <bits/stdc++.h> using namespace std; #define int long long using ll = long long; #define FOR(I, L, R) for(int I(L) ; I <= (int)R ; ++I) #define FOD(I, R, L) for(int I(R) ; I >= (int)L ; --I) #define FOA(I, A) for(auto &I : A) #define print(A,L,R) FOR(OK, L, R){if(A[OK]<=-oo / 10||A[OK]>=oo)cout<<"- ";else cout<<A[OK]<<' ';}cout<<'\n'; #define prints(A) FOA(OK, A){cout<<OK<<' ';}cout << '\n'; #define printz(A,L,R) FOR(OK, 0, L){FOR(KO, 0, R){if(A[OK][KO]>-oo&&A[OK][KO]<oo)cout<<A[OK][KO]<<' ';else cout << "- ";} cout << '\n';}cout << '\n'; #define fs first #define sd second #define ii pair<int,int> #define iii pair<int, ii> #define all(A) A.begin(), A.end() #define quickly ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define div alksdjf const int N = 5e5 + 5; const int mod = 1e9 + 7; const int oo = 1e9; int n, m, q; bool ans[N]; vector<int> curtain[N]; vector<ii> query[N]; struct Segment_tree{ int sg[N << 2]; void build(int id, int l, int r){ if(l == r){ sg[id] = oo; return; } int mid = (l + r) >> 1; build(id << 1, l, mid); build(id << 1 | 1, mid + 1, r); sg[id] = oo; } void update(int id, int l, int r, int u, int v){ if(l > v || r < u){ return; } if(u <= l && r <= v){ sg[id] = min(sg[id], v); return; } int mid = (l + r) >> 1; update(id << 1, l, mid, u, v); update(id << 1 | 1, mid + 1, r, u, v); sg[id] = min(sg[id], max(sg[id << 1], sg[id << 1 | 1])); } bool get(int id, int l, int r, int u, int v){ if(l > v || r < u){ return 1; } if(u <= l && r <= v){ return (sg[id] <= v); } int mid = (l + r) >> 1; return (get(id << 1, l, mid, u, v) & get(id << 1 | 1, mid + 1, r, u, v)); } } sg; signed main(){ quickly cin >> m >> n >> q; FOR(i, 1, n){ int l, r; cin >> l >> r; curtain[l].push_back(r); } FOR(i, 1, q){ int l, r; cin >> l >> r; query[l].push_back({r, i}); } sg.build(1, 1, m); FOD(l, m, 1){ FOA(r, curtain[l]){ sg.update(1, 1, m, l, r); } FOA(v, query[l]){ int r = v.fs, in = v.sd; ans[in] = sg.get(1, 1, m, l, r); } } FOR(i, 1, q){ cout << (ans[i] ? "YES\n" : "NO\n"); } }
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