제출 #1271454

#제출 시각아이디문제언어결과실행 시간메모리
1271454red_soulsSpring cleaning (CEOI20_cleaning)C++20
9 / 100
181 ms18756 KiB
#include <bits/stdc++.h> #define ll long long #define task "crt" using namespace std; const int N = 200000 + 16; int n, q, u, v, a[N]; vector<int> adj[N]; ll result; int leaves[N]; void preDfs(int k, int p) { if (adj[k].size() == 1) leaves[k] = 1; else leaves[k] = 0; for (auto to : adj[k]) { if (to == p) continue; preDfs(to, k); leaves[k] += leaves[to]; } } /* HLD */ int h[N], sz[N], par[N]; int chainId[N], chainArr[N], pos[N], chainHead[N], curPos = 1, curChain = 1, endPos[N]; int SZ; // số lượng vị trí hợp lệ sau HLD void dfs(int k, int p) { sz[k] = 1; par[k] = p; for (auto to : adj[k]) { if (to == p) continue; h[to] = h[k] + 1; dfs(to, k); sz[k] += sz[to]; } } void hld(int k, int p) { if (!chainHead[curChain]) chainHead[curChain] = k; chainId[k] = curChain; pos[k] = curPos; chainArr[curPos] = k; curPos++; int heaviest = 0; for (auto to : adj[k]) { if (to == p) continue; if (heaviest == 0 || sz[to] > sz[heaviest]) heaviest = to; } if (heaviest) hld(heaviest, k); for (auto to : adj[k]) { if (to == p || to == heaviest) continue; curChain++; hld(to, k); } endPos[k] = curPos - 1; } int lca(int u, int v) { // So sánh bằng đầu chuỗi theo độ sâu head (KHÔNG dùng chainId trực tiếp) while (chainHead[chainId[u]] != chainHead[chainId[v]]) { if (h[chainHead[chainId[u]]] > h[chainHead[chainId[v]]]) { u = par[chainHead[chainId[u]]]; } else { v = par[chainHead[chainId[v]]]; } } return (h[u] < h[v]) ? u : v; } struct node { int val = 0, lazy = 0; node operator + (const node &other) const { node ans; ans.val = val + other.val; return ans; } }; node segmentTree[(N << 2)]; void build(int k, int l, int r) { if (l == r) { if (l <= SZ && leaves[chainArr[l]] & 1) segmentTree[k].val = 1; else segmentTree[k].val = 0; segmentTree[k].lazy = 0; return; } int mid = (l + r) >> 1; build(k << 1, l, mid); build(k << 1 | 1, mid + 1, r); segmentTree[k] = segmentTree[k << 1] + segmentTree[k << 1 | 1]; segmentTree[k].lazy = 0; } void down(int k, int l, int r) { if (!segmentTree[k].lazy) return; int mid = (l + r) >> 1; // flip left child segmentTree[k << 1].val = (mid - l + 1) - segmentTree[k << 1].val; segmentTree[k << 1].lazy ^= 1; // flip right child segmentTree[k << 1 | 1].val = (r - mid) - segmentTree[k << 1 | 1].val; segmentTree[k << 1 | 1].lazy ^= 1; segmentTree[k].lazy = 0; } void update(int k, int l, int r, int x, int y) { if (l > y || x > r) return; if (l >= x && r <= y) { segmentTree[k].val = (r - l + 1) - segmentTree[k].val; segmentTree[k].lazy ^= 1; return; } int mid = (l + r) >> 1; down(k, l, r); update(k << 1, l, mid, x, y); update(k << 1 | 1, mid + 1, r, x, y); segmentTree[k] = segmentTree[k << 1] + segmentTree[k << 1 | 1]; } node getSeg(int k, int l, int r, int x, int y) { if (l > y || x > r) { return node(); } if (l >= x && r <= y) return segmentTree[k]; int mid = (l + r) >> 1; down(k, l, r); return getSeg(k << 1, l, mid, x, y) + getSeg(k << 1 | 1, mid + 1, r, x, y); } void updateTree(int u, int v) { int L = lca(u, v); while (chainId[u] != chainId[L]) { update(1, 1, SZ, pos[chainHead[chainId[u]]], pos[u]); u = par[chainHead[chainId[u]]]; } while (chainId[v] != chainId[L]) { update(1, 1, SZ, pos[chainHead[chainId[v]]], pos[v]); v = par[chainHead[chainId[v]]]; } if (h[u] < h[v]) update(1, 1, SZ, pos[u], pos[v]); else update(1, 1, SZ, pos[v], pos[u]); } node getTree(int u, int v) { node ans; int L = lca(u, v); while (chainId[u] != chainId[L]) { ans = getSeg(1, 1, SZ, pos[chainHead[chainId[u]]], pos[u]) + ans; u = par[chainHead[chainId[u]]]; } while (chainId[v] != chainId[L]) { ans = getSeg(1, 1, SZ, pos[chainHead[chainId[v]]], pos[v]) + ans; v = par[chainHead[chainId[v]]]; } if (h[u] < h[v]) ans = getSeg(1, 1, SZ, pos[u], pos[v]) + ans; else ans = getSeg(1, 1, SZ, pos[v], pos[u]) + ans; return ans; } node getSubtree(int u) { return getSeg(1, 1, SZ, pos[u], endPos[u]); } int leafCnt; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); if (fopen(task".inp", "r")) { freopen(task".inp", "r", stdin); freopen(task".out", "w", stdout); } cin >> n >> q; for (int i = 1; i < n; i++) { cin >> u >> v; adj[u].push_back(v); adj[v].push_back(u); } preDfs(1, 1); // chuẩn bị HLD h[1] = 0; par[1] = 1; dfs(1, 1); hld(1, 1); SZ = curPos - 1; // số vị trí thực sự dùng (1..SZ) build(1, 1, SZ); for (int i = 1; i <= n; i++) if (adj[i].size() == 1) leafCnt++; while (q--) { int d; cin >> d; for (int i = 1; i <= d; i++) cin >> a[i]; set<int> distinct; for (int i = 1; i <= d; i++) { updateTree(1, a[i]); // toggle path 1..a[i] if (adj[a[i]].size() == 1) distinct.insert(a[i]); } if ((leafCnt - (int)distinct.size() + d) & 1) { result = -1; } else { ll oddAll = getSubtree(1).val + d; // số node có odd (bao gồm n+i) ll evenSum = 2LL * (n + d - oddAll); result = oddAll + evenSum; // = 2*(n+d) - oddAll // chuyển về công thức đúng (loại node 1 khỏi tổng theo công thức gốc) if (getTree(1, 1).val == 1) result -= 1; else result -= 2; } cout << result << '\n'; // rollback (toggle lại) for (int i = 1; i <= d; i++) updateTree(1, a[i]); } return 0; }

컴파일 시 표준 에러 (stderr) 메시지

cleaning.cpp: In function 'int main()':
cleaning.cpp:174:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  174 |         freopen(task".inp", "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
cleaning.cpp:175:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  175 |         freopen(task".out", "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
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