이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include"holiday.h"
#include<string.h>
#include<algorithm>
using namespace std;
int top,ch,s,t=1,pos[100001],k,e,p2[530001],r=1;
long long dap,r1[530001],l1[530001],r2[530001],l2[530001],p[530001];
struct data{
int x,y;
bool operator<(const data&r)const{
return x>r.x;
}
}a[100001];
struct data2{
int num;
long long sum;
}tree[270010];
struct data3{
int x,y,m1,m2;
}st[530010];
struct data3 st2[530010];
void update(int x){
int p=x+t-1;
if(tree[p].num) return;
while(p>0){
tree[p].num++; tree[p].sum+=a[x].x;
p/=2;
}
}
void finding(int x,int y,int k,int num){
if(k==1 && num==0){s=0; return;}
if(x==y){s=x-1; return;}
if(num-tree[k*2].num>=0)
{
finding((x+y)/2+1,y,k*2+1,num-tree[k*2].num);
}
else finding(x,(x+y)/2,k*2,num);
}
long long query(int x,int y,int k,int s,int e){
if(s<=x && y<=e) return tree[k].sum;
if(s>y || e<x) return 0;
return query(x,(x+y)/2,k*2,s,e)+query((x+y)/2+1,y,k*2+1,s,e);
}
void gap(int m,int x,int y,int sw){
int i,ps=x;
long long maxi=0;
for(i=e+1;i<x;i++) update(pos[i]);
for(i=x;i<=y;i++)
{
ch=0; update(pos[i]);
if(sw==1) finding(1,t,1,m-(i-1));
else finding(1,t,1,m-(i-1)*2);
if(maxi<query(1,t,1,1,s))
{
maxi=query(1,t,1,1,s);
ps=i;
}
}
e=y;
p[m]=maxi; p2[m]=ps;
}
void ins(int i)
{
int m=(st[i].m1+st[i].m2)/2;
st2[i*2-1].m1=st[i].m1; st2[i*2-1].m2=m;
st2[i*2-1].x=st[i].x; st2[i*2-1].y=p2[m];
st2[i*2].m1=m+1; st2[i*2].m2=st[i].m2;
st2[i*2].x=p2[m]; st2[i*2].y=st[i].y;
}
void pro(int m1,int m2,int x,int y,int sw){
int i,m;
top=1; st[top].m1=m1; st[top].m2=m2; st[top].x=x; st[top].y=y;
while(1)
{
memset(tree,0,sizeof tree);
if(st[1].m1==st[1].m2) return;
e=0;
for(i=1;i<=top;i++){
m=(st[i].m1+st[i].m2)/2;
gap(m,st[i].x,st[i].y,sw);
}
for(i=1;i<=top;i++){
ins(i);
}
top*=2;
for(i=1;i<=top;i++) st[i]=st2[i];
}
}
long long int findMaxAttraction(int n, int st, int d, int att[])
{
int i;
for(i=st-1;i>=0;i--) a[st-i].x=att[i], a[st-i].y=st-i;
sort(a+1,a+st+1); for(i=1;i<=st;i++) pos[a[i].y]=i;
for(i=1;;i++){if(r>=st*3) break; r*=2;}
for(i=1;;i++){if(t>=st) break; t*=2;}
pro(1,r,1,st,1); for(i=1;i<=r;i++) l1[i]=p[i];
pro(1,r,1,st,2); for(i=1;i<=r;i++) l2[i]=p[i];
for(i=st+1;i<n;i++) a[i-st].x=att[i], a[i-st].y=i-st;
sort(a+1,a+n-st); for(i=1;i<=n-st-1;i++) pos[a[i].y]=i;
for(i=1;;i++){if(r>=(n-st-1)*3) break; r*=2;}
for(i=1;;i++){if(t>=n-st-1) break; t*=2;}
pro(1,r,1,n-st-1,1); for(i=1;i<=r;i++) r1[i]=p[i];
pro(1,r,1,n-st-1,2); for(i=1;i<=r;i++) r2[i]=p[i];
for(i=0;i<=d;i++){
dap=max(dap,l1[i]+r2[d-i]);
dap=max(dap,l2[i]+r1[d-i]);
if(i>=1) dap=max(dap,l1[i-1]+r2[d-i]+att[st]);
if(i>=1) dap=max(dap,l2[i-1]+r1[d-i]+att[st]);
}
return dap;
}
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