제출 #126822

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
126822		MohamedAhmed04	Examination (JOI19_examination)	C++14	0 / 100	3026 ms	198620 KiB

examination

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
using namespace std;

const int MAX = 1e5 + 5 ;

struct chash {
    int operator()(pair<int , int> x) const { return x.first* 31 + x.second; }
};

gp_hash_table<pair<int , int> , int, chash> bit;

void update(int x , int y , int val)
{
    while(x < MAX)
    {
        int y1 = y ;
        while(y1 < MAX)
        {
            bit[{x , y1}] += val ;
            y1 += (y1 & -y1) ;
        }
        x += (x & -x) ;
    }
    return ;
}

int query(int x , int y)
{
    int ans = 0 ;
    while(x > 0)
    {
        int y1 = y ;
        while(y1 > 0)
        {
            ans += bit[{x , y1}] ;
            y1 -= (y1 & -y1) ;
        }
        x -= (x & -x) ;
    }
    return ans ;
}

int main()
{
    int n , q ;
    scanf("%d %d" , &n , &q) ;
    int a[n] , b[n] ;
    for(int i = 0 ; i < n ; ++i)
    {
        scanf("%d %d" , &a[i] , &b[i]) ;
        update(a[i] , b[i] , 1) ;
    }
    const int N = 1e5 ;
    int cur = query(N , N) ;
    while(q--)
    {
        int x , y , z ;
        scanf("%d %d %d" , &x , &y , &z) ;
        printf("%d\n" , cur - query(x-1 , N) - query(N , y-1) + query(x-1 , y-1)) ;
    }
    return 0 ;
}

컴파일 시 표준 에러 (stderr) 메시지

examination.cpp: In function 'int main()':
examination.cpp:48:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d" , &n , &q) ;
     ~~~~~^~~~~~~~~~~~~~~~~~~
examination.cpp:52:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d %d" , &a[i] , &b[i]) ;
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
examination.cpp:60:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d %d %d" , &x , &y , &z) ;
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~

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• Subtask 2: 0 / 20
• Subtask 3: 0 / 21
• Subtask 4: 0 / 57