제출 #1267350

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1267350		_filya_	Synchronization (JOI13_synchronization)	C++20	0 / 100	1887 ms	26096 KiB

synchronization

#include<bits/stdc++.h>
typedef long long ll;
using namespace std;
const int N = 1e5 + 50;

struct segtree {
 
	vector<long long> lazy, sum;
	int size = 1;
 
	void init(int n) {
		while (size < n) {
			size *= 2;
		}
		lazy.assign(2 * size - 1, 0ll);
		sum.assign(2 * size - 1, 0ll);
	}
 
	void prop(int x, int lx, int rx) {
		if (rx - lx == 1) {
			lazy[x] = 0;
			return;
		}
		lazy[2 * x + 1] += lazy[x];
		lazy[2 * x + 2] += lazy[x];
		sum[2 * x + 1] += lazy[x] * static_cast<long long>(rx - lx) / 2;
		sum[2 * x + 2] += lazy[x] * static_cast<long long>(rx - lx) / 2;
		lazy[x] = 0;
	}
 
	void add(int l, int r, ll v, int x, int lx, int rx) {
		if (lx >= l && rx <= r) {
			lazy[x] += v;
			sum[x] += v * static_cast<long long>(rx - lx);
			return;
		}
		if (rx <= l || lx >= r) {
			return;
		}
		int m = (rx + lx) / 2;
		add(l, r, v, 2 * x + 1, lx, m);
		add(l, r, v, 2 * x + 2, m, rx);
		sum[x] = sum[2 * x + 1] + sum[2 * x + 2] + lazy[x] * (rx - lx);
	}
 
	void add(int l, int r, ll val) {
		add(l, r, val, 0, 0, size);
	}
 
	ll query(ll l, ll r, int x, ll lx, ll rx) {
		prop(x, lx, rx);
		if (lx >= l && rx <= r) {
			return sum[x];
		}
		if (rx <= l || lx >= r) {
			return 0ll;
		}
		int m = (rx + lx) / 2;
		ll s1 = query(l, r, 2 * x + 1, lx, m);
		ll s2 = query(l, r, 2 * x + 2, m, rx);
		return s1 + s2 + lazy[x] * (rx - lx);
	}
 
	ll query(ll l, ll r) {
		return query(l, r, 0, 0, size);
	}
} tree1, tree2;

int last[N], ans[N], par[N], root[N], depth[N], sz[N], pos[N], rpos[N], ti = 0; 
vector<int> G[N];

void dfsSz(int s, int p) {
    sz[s] = 1;
    depth[s] = depth[p] + 1;
    par[s] = p;
    if (root[s] == -1) root[s] = s;
    for (auto& u : G[s]) {
        if (u == p) continue;
        dfsSz(u, s);
        sz[s] += sz[u];
        if (sz[u] > sz[G[s][0]]) swap(G[s][0], u);
    }
}

void dfsHld(int s, int p) {
    pos[s] = ++ti;
    rpos[ti] = s;
    for (auto u : G[s]) {
        if (u == p) continue;
        root[u] = (u == G[s][0] ? root[s] : u);
        dfsHld(u, s);
    }
}

int highest_ancesor(int u) {
    if (tree1.query(pos[root[u]], pos[u] + 1) == pos[u] - pos[root[u]]) {
        return root[u];
    } 
    int l = pos[root[u]] - 1, r = pos[u];
    while(r - l > 1) {
        int mid = (r + l + 1) / 2;
        if (tree1.query(mid, pos[u] + 1) != pos[u] - mid) {
            l = mid;
        } else {
            r = mid;
        }
    }
    return rpos[r];
}

void query1(int u) {
    int s = u;
    int dif = tree2.query(pos[s], pos[s] + 1) - last[s];
    while(s != -1) {
        int h = highest_ancesor(s);
        tree2.add(pos[h], pos[s] + 1 - (s == u), dif);
        if (h != root[s] || !h || tree1.query(pos[h], pos[s] + 1) != pos[s] - pos[h] + 1) {
            break;
        }
        s = par[root[s]];
    }
}

int query2(int s) {
    while(s != -1) {
        int h = highest_ancesor(s);
        if (h != root[s] || !h || tree1.query(pos[h], pos[s] + 1) != pos[s] - pos[h] + 1) {
            return h;
        }
        s = par[root[s]];
    }
    return 0;
}

int main()
{
// 	ifstream cin("input.txt");
//     ofstream cout("output.txt");
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	cout.tie(nullptr);
	int n, m, q; cin >> n >> m >> q;
    vector<array<int, 2>> edges;
    for (int i = 0; i < n - 1; i++) {
        int u, v; cin >> u >> v;
        u--; v--;
        G[u].push_back(v);
        G[v].push_back(u);
        edges.push_back({u, v});
    }
    dfsSz(0, -1);
    dfsHld(0, -1);
    tree1.init(n + 1);
    tree2.init(n + 1);
    for (int i = 0; i < n; i++) {
        ans[i] = 1;
        last[i] = 0;
        tree2.add(pos[i], pos[i] + 1, 1);
    }
    for (auto& e : edges) {
        if (e[0] == par[e[1]]) swap(e[0], e[1]);
    }
    while(m--) {
        int e; cin >> e; e--;
        auto [u, v] = edges[e];
        if (tree1.query(pos[u], pos[u] + 1) == 0) {
            tree1.add(pos[u], pos[u] + 1, 1);
            query1(u);
        } else {
            int anc = query2(u);
            last[u] = tree2.query(pos[u], pos[u] + 1);
            ll pl = tree2.query(pos[anc], pos[anc] + 1) - last[u];
            tree2.add(pos[u], pos[u] + 1, pl);
            tree1.add(pos[u], pos[u] + 1, -1);
        }
    }
    while(q--) {
        int u; cin >> u; u--;
        int anc = query2(u);
        cout << tree2.query(pos[anc], pos[anc] + 1) << '\n';
    }
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 20
• Subtask 3: 0 / 10
• Subtask 4: 0 / 20
• Subtask 5: 0 / 40