Submission #126609

#	Time	Username	Problem	Language	Result	Execution time	Memory
126609		dndhk	Two Transportations (JOI19_transportations)	C++14	0 / 100	1340 ms	61200 KiB

Azer

#include "Azer.h"
#include <bits/stdc++.h>

#define pb push_back
#define all(v) ((v).begin(), (v).end())
#define sortv(v) sort(all(v))
#define sz(v) ((int)(v).size())
#define uniqv(v) (v).erase(unique(all(v)), (v).end())
#define umax(a, b) (a)=max((a), (b))
#define umin(a, b) (a)=min((a), (b))
#define FOR(i,a,b) for(int i = (a); i <= (b); i++)
#define rep(i,n) FOR(i,1,n)
#define rep0(i,n) FOR(i,0,(int)(n)-1)
#define FI first
#define SE second
#define INF 2000000000
#define INFLL 1000000000000000000LL


using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const int MAX_N = 2000;
const int LOG_N = 11;
const int LOG_D = 20;
namespace {

    int N;
    vector<pii> gp[MAX_N+1];
    int dist[MAX_N+1];
    int vst[MAX_N+1];
    int n=0, d=0, cnt=0;
    int n2=0, d2=0;
    bool finish = false;
    int two = 1;

    void calc(){
        for(int i=0; i<gp[n].size(); i++){
          if(dist[gp[n][i].first]>dist[n] + gp[n][i].second){
            dist[gp[n][i].first] = dist[n] + gp[n][i].second;
          }
        }
        n2 = 0;
        d2 = (1<<LOG_D)-1;
        finish = true;
        for(int i=0; i<N; i++){
            if(!vst[i]) finish = false;
            if(vst[i])  continue;
            if(dist[i] < d2){
              d2 = dist[i];
              n2 = i;
            }
        }
    }

    void make_ans(){
      bool b = true;
        //cout<<n<<" "<<d<<endl;
        //cout<<n2<<" "<<d2<<endl<<endl;
        if(d<d2){
            dist[n] = d;
            vst[n] = true;
        }else{
            b = false;
            dist[n2] = d2;
            n = n2; d = d2;
            vst[n] = true;
        }
        calc();
        if(finish){
          Answer();
          return;
        }
        if(b){
          n = d = cnt = 0;
          two = 1;
          SendA(1);
          return;
        }
        SendA(0);
        //cout<<n<<" "<<d<<endl;
        for(int i=0; i<LOG_N; i++){
          SendA((bool)(n%2)); n/=2;
        }for(int i=0; i<LOG_D; i++){
          SendA((bool)(d%2)); d/=2;
        }
        n = d = cnt = 0;
        two = 1;
    }

}   

void InitA(int N, int A, vector<int> U, vector<int> V, vector<int> C) {
    ::N = N;
    for (int i = 0; i < A; ++i) {
        gp[U[i]].pb({V[i], C[i]});
        gp[V[i]].pb({U[i], C[i]});
    }
    vst[0] = 1;
    dist[0] = 0;
    for(int i=1; i<N; i++){
        dist[i] = (1<<LOG_D)-1;
    }
    calc();
}


void ReceiveA(bool x) {
    if(cnt<LOG_N){
        n += (int)x * two;
        two*=2;
    }else if(cnt < LOG_D+LOG_N){
        d += (int)x * two;
        two*=2;
    }
    cnt++;
    if(cnt==LOG_N){
      two = 1;
    }
    if(cnt==LOG_D+LOG_N){
        make_ans();
    }
}

vector<int> Answer() {
  vector<int> ans(N);
  for(int i=0; i<N; i++){
    ans[i] = dist[i];
  }
  return ans;
}

Baijan

#include "Baijan.h"
#include <bits/stdc++.h>

#define pb push_back
#define all(v) ((v).begin(), (v).end())
#define sortv(v) sort(all(v))
#define sz(v) ((int)(v).size())
#define uniqv(v) (v).erase(unique(all(v)), (v).end())
#define umax(a, b) (a)=max((a), (b))
#define umin(a, b) (a)=min((a), (b))
#define FOR(i,a,b) for(int i = (a); i <= (b); i++)
#define rep(i,n) FOR(i,1,n)
#define rep0(i,n) FOR(i,0,(int)(n)-1)
#define FI first
#define SE second
#define INF 2000000000
#define INFLL 1000000000000000000LL


using namespace std;

const int MAX_N = 2000;
const int LOG_N = 11;
const int LOG_D = 20;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

namespace {
	int N;
    vector<pii> gp[MAX_N+1];
    int dist[MAX_N+1];
    int vst[MAX_N+1];
    int n=0, d=0, cnt=0;
    int two = 1;
    bool finish = false;
    void calc2(){
        for(int i=0; i<gp[n].size(); i++){
          if(dist[gp[n][i].first]>dist[n] + gp[n][i].second){
            dist[gp[n][i].first] = dist[n] + gp[n][i].second;
          }
        }
        n = 0;
        d = (1<<LOG_D)-1;
        for(int i=0; i<N; i++){
            if(vst[i])  continue;
            if(dist[i] < d){
              d = dist[i];
              n = i;
            }
        }
    }
    void make_ans2(){
    	vst[n] = true;
    	dist[n] = d;
 		//cout<<"*"<<n<<" "<<d<<" "<<endl;
    	calc2();
 		//cout<<"*"<<n<<" "<<d<<" "<<endl;
    	int n2 = n, d2 = d;
    	for(int i=0; i<LOG_N; i++){
 			SendB((bool)(n2%2)); n2/=2;
	 	}
	 	for(int i=0; i<LOG_D; i++){
	 		SendB((bool)(d2%2)); d2/=2;
	 	}
	 	cnt = 0;
    }
} 

void InitB(int N, int B, vector<int> S, vector<int> T, vector<int> D) {
 	::N = N;
 	for(int i=0; i<B; i++){
 		gp[S[i]].pb({T[i], D[i]});
 		gp[T[i]].pb({S[i], D[i]});
 	}
 	vst[0] = true;
 	for(int i=1; i<N; i++)	dist[i] = (1<<LOG_D)-1;
 	calc2();
 	int n2 = n, d2 = d;
 	//cout<<"*"<<n<<" "<<d<<" "<<endl;
 	for(int i=0; i<LOG_N; i++){
 		SendB((bool)(n2%2)); n2/=2;
 	}
 	for(int i=0; i<LOG_D; i++){
 		SendB((bool)(d2%2)); d2/=2;
 	}
 	cnt = 0;
}

void ReceiveB(bool y) {
	if(cnt==0){
		if(y==1){
			make_ans2();
		}else{
			n = d = 0;
			two = 1;
			cnt++;
		}
		return;
	}
	//cout<<"#"<<cnt<<" "<<y<<endl;
	if(cnt<=LOG_N){
		n += (int)y*two;
	}else if(cnt<=LOG_D+LOG_N){
		d += (int)y*two;
	}
	two*=2;
	cnt++;
	if(cnt==LOG_N+1){
		two = 1;
	}
	if(cnt==LOG_D+LOG_N+1){
		make_ans2();
	}
}

Compilation message (stderr)

Azer.cpp: In function 'void {anonymous}::calc()':
Azer.cpp:40:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(int i=0; i<gp[n].size(); i++){
                      ~^~~~~~~~~~~~~

Baijan.cpp: In function 'void {anonymous}::calc2()':
Baijan.cpp:39:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for(int i=0; i<gp[n].size(); i++){
                      ~^~~~~~~~~~~~~
Baijan.cpp: At global scope:
Baijan.cpp:37:10: warning: '{anonymous}::finish' defined but not used [-Wunused-variable]
     bool finish = false;
          ^~~~~~

• Subtask 1: 0 / 6
• Subtask 2: 0 / 8
• Subtask 3: 0 / 8
• Subtask 4: 0 / 38
• Subtask 5: 0 / 14
• Subtask 6: 0 / 10
• Subtask 7: 0 / 16