Submission #1260660

#	Time	Username	Problem	Language	Result	Execution time	Memory
1260660		tminh	Factories (JOI14_factories)	C++20	0 / 100	2953 ms	69944 KiB

factories

#include "bits/stdc++.h"
#include "factories.h"
using namespace std;

#define task ""
#define ll long long
#define endl '\n'
#define fi first
#define se second
#define vall(a) (a).begin(), (a).end()
#define sze(a) (int)a.size()
#define pii pair<int, int>
#define pll pair<ll, ll>


#define ep emplace_back
#define pb push_back
#define pf push_front


const ll mod = 1e9 + 7;
const int N = 5e5 + 5;
const ll oo = 1e18;

bool START;

int n, q, par[N], sz[N];
vector<pii> adj[N];

set<ll> s[N];
bool del[N];

map<int, ll> d[N];


int get_sz(int u, int p = 0) {
	sz[u] = 1;
	for (auto[v, w] : adj[u]) {
		if (v == p || del[v]) continue;
		sz[u] += get_sz(v, u);
	}
	return sz[u];
}

int get_cen(int sigma, int u, int p = 0) {
	for (auto[v, w] : adj[u]) {
		if (v != p && !del[v] && sz[v] * 2 > sigma) return get_cen(sigma, v, u);
	}
	return u;
}

void make_dist(int u, int p, int root, ll depth) {
	d[root][u] = depth;
	for (auto[v, w] : adj[u]) {
		if (v == p || del[v]) continue;
		make_dist(v, u, root, depth + w);
	}
}

int centroid(int u) {
	u = get_cen(get_sz(u), u);
	del[u] = true;
	
	d[u][u] = 0;
	for (auto[v, w] : adj[u]) {
		if (del[v]) continue;
		make_dist(v, u, u, w);
	}
	
	for (auto[v, w] : adj[u]) {
		if (del[v]) continue;
		int x = centroid(v);
		par[x] = u;
	}
	return u;
}



void Init(int N, int A[], int B[], int D[]){
	for (int i = 0; i < N - 1; ++i) {
		adj[A[i]].pb(make_pair(B[i], D[i]));
		adj[B[i]].pb(make_pair(A[i], D[i]));
	}
	centroid(0);
	return;
}


long long Query(int S, int X[], int T, int Y[]){
	for (int i = 0; i < S; ++i) {
		int u = X[i];
		int p = u;
		
		while(p != 0) {
			s[p].insert(d[p][u]);
			p = par[p];
		}
	}
	ll ans = oo;
	for (int i = 0; i < T; ++i) {
		int u = Y[i];
		int p = u;
		
		while(p != 0) {
			if (!s[p].empty()) ans = min(ans, *s[p].begin() + d[p][u]);
			p = par[p];
		}
	}
	for (int i = 0; i < S; ++i) {
		int u = X[i];
		int p = u;
		
		while(p != 0) {
			s[p].erase(d[p][u]);
			p = par[p];
		}
	}
	return ans;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 18
• Subtask 3: 0 / 67