제출 #1260388

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1260388		yf_yusuf	Palembang Bridges (APIO15_bridge)	C++20	63 / 100	2088 ms	12148 KiB

bridge

//```//    YF YUSUF
#define YF ios_base::sync_with_stdio(0);cout.setf(ios::fixed);
#define YUSUF cout.precision(0);cout.tie(0);cin.tie(0);
#include <bits/stdc++.h>
// #include <iostream>
// #include <vector>
// #include <set>
// #include <map>
// #include <algorithm>
// #include <unordered_map>
// #include <cmath>
// #include <numeric>
// #include <queue>
// #include <stack>
// #include <cassert>
// #include <climits>
// #include <string>
// #include <cstdlib>
using namespace std;
#ifdef YF_CHECK
	bool Output=1;
//	#include "g/debug.h"
//  #include "g/bigint.h"
//	#include "g/text.h"
#else
	#pragma GCC optimize ("unroll-loops")
	#pragma GCC optimize ("inline")
	#pragma GCC optimize ("Ofast")
	#pragma GCC optimize ("O3")
	bool Output=0;
	#define deb(x...) 42 
#endif
#ifdef DEV
	bool LOUT=1;
#else
	bool LOUT=0;
#endif
using ll   = long long;
using ld   = long double;
using sll  = set <ll>;
using vll  = vector <ll>;
using mll  = map <ll,ll>;
using pll  = pair <ll,ll>;
using vvl  = vector <vll>;
using vpll = vector <pll>;
template<class T>T MIN(T&a,T b){a=min(a,b);return a;}
template<class T>T MAX(T&a,T b){a=max(a,b);return a;}
#define revers(a) reverse(all(a))
#define all(a) a.begin(),a.end()
#define sortt(a) sort(all(a))
#define sgr v+v+1,(tl+tr)/2+1,tr
#define sgl v+v,tl,(tl+tr)/2
#define pb push_back
#define ins insert
#define S second
#define F first
ll BP(ll a,ll b,ll mod=1e9+7){
	if(b==0)return 1;
	ll q=BP(a,b/2,mod);
	return ((q*q)%mod*(b%2?a:1ll))%mod;
}
ll f(ll x){return x*(x+1)/2;}
ll dup(ll a,ll b){return (a+b-1)/b;}
ll lcm(ll a,ll b){return a/__gcd(a,b)*b;}
ll invf(ll x){return (-1+sqrt(1+8*x))/2;}
ll log(ll x){return 63 - __builtin_clzll(x);}
const ll  mod=998244353;
const ll  INF=1e18;
const ll  inf=1e9+7;
const ll  N  =1e6+7;
ll n,k;
void YF_MAIN(ll TEST){
	cin>>k>>n;
	ll sum = 0, add = 10 * n * inf;
	vvl V;
	for(int i=1;i<=n;i++){
		char a,b;
		ll v,u;
		cin>>a>>v>>b>>u;
		sum+=abs(v - u);
		if(a==b)continue;
		if(v>u)swap(v, u);
		V.pb({v+u,v,u});
		sum++;
	}
	sortt(V);
	ll m = V.size();
	if(!m){
		cout<<sum;
		return;
	}
	if(k==2){
		for(int k=0;k<m-1;k++){
			vpll a,b;
			vll A,B;
			for(int i=0;i<m;i++){
				(i<=k ? a : b).pb({V[i][1], V[i][2]});
			}
			for(auto [f,s] : a){
				A.pb(f);
				A.pb(s);
			}
			for(auto [f,s] : b){
				B.pb(f);
				B.pb(s);
			}
			sortt(A);ll aa = A[A.size()/2];
			sortt(B);ll bb = B[B.size()/2];
			ll now = 0;
			for(auto [f, s] : a){
				if(f<=aa && aa<=s)continue;
				now += min(abs(f-aa),abs(s-aa));
			}
			for(auto [f, s] : b){
				if(f<=bb && bb<=s)continue;
				now += min(abs(f-bb),abs(s-bb));
			}
			MIN(add, now);
		}
	}
	else{
		vpll a;
		vll A;
		for(int i=0;i<m;i++){
			a.pb({V[i][1], V[i][2]});
		}
		for(auto [f,s] : a){
			A.pb(f);
			A.pb(s);
		}
		sortt(A);ll aa = A[A.size()/2];
		ll now = 0;
		for(auto [f, s] : a){
			if(f<=aa && aa<=s)continue;
			now += min(abs(f-aa),abs(s-aa));
		}
		MIN(add, now);
	}
	cout<<sum + add*2;
}
bool TECT=0;
bool CASE=0;
bool OUTP=1;
const ll LN=1e1 + 7; ll lg[LN];
const ll SN=2e1 + 7; ll SM[SN];
const ll FN=2e1 + 7; 
ll FACT[FN],inv[FN],FMOD=inf;
ll PER(ll n,ll k){return FACT[n] *inv[n-k]%FMOD;}
ll CNK(ll n,ll k){return PER(n,k)*inv[k  ]%FMOD;}
void BEFORE(){
	for(ll i=2;i<SN;i++){
		if(SM[i])continue;
		for(ll j=i;j<SN;j+=i)
			MAX(SM[j],i);
	}
	for(int i=2;i<LN;i++) lg[i]=lg[i/2]+1;
	FACT[0]=inv[0]=1;
	for(int i=1;i<FN;i++){
		FACT[i]=FACT[i-1]*i%FMOD;
		if(i<5e5+7)inv[i]=BP(FACT[i],FMOD-2,FMOD);
	}
}
signed main(){
	if(OUTP){YF YUSUF}
	// freopen((".in"),"r",stdin);freopen((".out"),"w",stdout);
	cout<<(LOUT && Output ? "\nYF_OUTPUT:\n\n" : "");
	int TEST=1;
	if(TECT)
		cin>>TEST;
	BEFORE();
	for(int T=1;T<=TEST;T++){
		if(CASE)
			cout<<"Case "<<T<<": ";
		YF_MAIN(T);
		cout<<(T==TEST ? "" : "\n");
	}
	return 0;
} 
//```

• Subtask 1: 8 / 8
• Subtask 2: 14 / 14
• Subtask 3: 9 / 9
• Subtask 4: 32 / 32
• Subtask 5: 0 / 37