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답안 #125764

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
125764 2019-07-06T10:24:14 Z eriksuenderhauf Nuclearia (CEOI15_nuclearia) C++11
55 / 100
 1000 ms 440620 KB 
//#pragma GCC optimize("O3")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define mem(a,v) memset((a), (v), sizeof (a))
#define enl printf("\n")
#define case(t) printf("Case #%d: ", (t))
#define ni(n) scanf("%d", &(n))
#define nl(n) scanf("%lld", &(n))
#define nai(a, n) for (int i = 0; i < (n); i++) ni(a[i])
#define nal(a, n) for (int i = 0; i < (n); i++) nl(a[i])
#define pri(n) printf("%d\n", (n))
#define prl(n) printf("%lld\n", (n))
#define pii pair<int, int>
#define pil pair<int, long long>
#define pll pair<long long, long long>
#define vii vector<pii>
#define vil vector<pil>
#define vll vector<pll>
#define vi vector<int>
#define vl vector<long long>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef cc_hash_table<int,int,hash<int>> ht;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> oset;
const double pi = acos(-1);
const int MOD = 1e9 + 7;
const int INF = 1e9 + 7;
const int MAXN = 1e6 + 5;
const double eps = 1e-9;
vector<vl> off, sl, sm, d1, d2;
vector<vl> offC, slC;

int main() {
	int w, h, n;
	scanf("%d %d %d", &w, &h, &n);
	off.resize(h+1); sl.resize(h+1), sm.resize(h+1);
	d1.resize(h+3), d2.resize(h+3), offC.resize(h+3), slC.resize(h+3);
	for (int i = 0; i <= h; i++)
		off[i].resize(w+3), sl[i].resize(w+3), sm[i].resize(w+3);
	for (int i = 0; i <= h+2; i++) {
		d1[i].resize(w+3), d2[i].resize(w+3);
		offC[i].resize(w+3), slC[i].resize(w+3);
	}
	for (int i = 0; i < n; i++) {
		ll x, y, a, b;
		scanf("%lld %lld %lld %lld", &x, &y, &a, &b);
		ll l = max(1ll, x - a / b), r = min((ll)w, x + a / b);
		ll c = max(1ll, y - a / b), d = min((ll)h, y + a / b);
		if (x-abs(y-c) < 1ll) {
			d1[y-x+1][2] -= b;
		} else
			d1[c][x-abs(y-c)+1] -= b;
		if (x-abs(y-d) < 1ll) {
			d2[x+y-1][2] -= b;
		} else
			d2[d][x-abs(y-d)+1] -= b;
		if (x+abs(y-d) > (ll)w) {
			d1[w+y-x+1][w+2] += b;
		} else
			d1[d+1][x+abs(y-d)+2] += b;
		if (x+abs(y-c) > (ll)w) {
			d2[x+y-w-1][w+2] += b;
		} else
			d2[c-1][x+abs(y-c)+2] += b;
		offC[c][l] += a;
		offC[d+1][l] -= a;
		offC[c][r+1] -= a;
		offC[d+1][r+1] += a;
		slC[c][l] -= abs(y-c) * b;
		slC[c+1][l] += abs(y-c) * b + b;
		slC[y+1][l] -= 2 * b;
		slC[d+1][l] += abs(y-d) * b + b;
		slC[d+2][l] -= abs(y-d) * b;
		slC[c][r+1] += abs(y-c) * b;
		slC[c+1][r+1] -= abs(y-c) * b + b;
		slC[y+1][r+1] += 2 * b;
		slC[d+1][r+1] -= abs(y-d) * b + b;
		slC[d+2][r+1] += abs(y-d) * b;
		for (ll j = c; j <= d; j++) {
			ll lo = max(1ll, x-abs(y-j));
			sl[j][l] -= b * (lo-l);
			sl[j][l+1] += b * (lo-l+1);
			if (x - abs(y-j) < 1ll)
				sl[j][lo+1] -= b;

			ll hi = min((ll)w, x+abs(y-j));
			if (x+abs(y-j) > (ll)w)
				sl[j][hi+1] -= b;
			sl[j][r+1] += b*(r-hi+1);
			sl[j][r+2] -= b*(r-hi);
		}
	}
	//cerr << "\n";
	for (int i = 1; i <= h; i++) {
		for (int j = 1; j <= w; j++) {
			d1[i][j] += d1[i-1][j-1];
			offC[i][j] += offC[i-1][j];
			slC[i][j] += slC[i-1][j];
			//cerr << i << " " << j << " " << slC[i][j] << "\n";
		}
	}
	for (int i = 1; i <= h; i++)
		for (int j = 1; j <= w; j++) {
			slC[i][j] += slC[i-1][j];
			//cerr << i << " " << j << " " << slC[i][j] << "\n";
		}
	for (int i = h-1; i > 0; i--)
		for (int j = 1; j <= w; j++)
			d2[i][j] += d2[i+1][j-1];
	for (int i = 1; i <= h; i++) {
		for (int j = 1; j <= w; j++) {
			sl[i][j] += d1[i][j] + d2[i][j];
			off[i][j] += offC[i][j] + slC[i][j];
			off[i][j] += off[i][j-1];
			sl[i][j] += sl[i][j-1];
		}
		for (int j = 1; j <= w; j++)
			sl[i][j] += sl[i][j-1];
		for (int j = 1; j <= w; j++)
			sm[i][j] = sm[i-1][j] + sm[i][j-1] - sm[i-1][j-1] + sl[i][j] + off[i][j];
	}
	int q; ni(q);
	while (q--) {
		ll x1, y1, x2, y2;
		scanf("%lld %lld %lld %lld", &x1, &y1, &x2, &y2);
		ll ans = sm[y2][x2] - sm[y1-1][x2] - sm[y2][x1-1] + sm[y1-1][x1-1];
		x1 = (x2-x1+1) * (y2-y1+1);
		if ((ans % x1) * 2 >= x1)
			prl(ans / x1 + 1);
		else
			prl(ans / x1);
	}
    return 0;
}

Compilation message

nuclearia.cpp: In function 'int main()':
nuclearia.cpp:42:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d %d", &w, &h, &n);
  ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
nuclearia.cpp:53:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%lld %lld %lld %lld", &x, &y, &a, &b);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
nuclearia.cpp:9:20: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define ni(n) scanf("%d", &(n))
               ~~~~~^~~~~~~~~~~~
nuclearia.cpp:129:9: note: in expansion of macro 'ni'
  int q; ni(q);
         ^~
nuclearia.cpp:132:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%lld %lld %lld %lld", &x1, &y1, &x2, &y2);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 398 ms 431096 KB Output is correct
2 Correct 100 ms 4600 KB Output is correct
3 Correct 87 ms 3832 KB Output is correct

Subtask #2
2.0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 395 ms 430932 KB Output is correct
2 Correct 99 ms 4600 KB Output is correct

Subtask #3
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 168 ms 138292 KB Output is correct
2 Correct 96 ms 4344 KB Output is correct

Subtask #4
2.0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 528 ms 185332 KB Output is correct
2 Correct 99 ms 4668 KB Output is correct

Subtask #5
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 559 ms 436992 KB Output is correct
2 Correct 106 ms 5376 KB Output is correct

Subtask #6
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 305 ms 178480 KB Output is correct
2 Correct 99 ms 4688 KB Output is correct

Subtask #7
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 330 ms 144956 KB Output is correct
2 Correct 104 ms 5000 KB Output is correct

Subtask #8
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 292 ms 119684 KB Output is correct
2 Correct 97 ms 4312 KB Output is correct

Subtask #9
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 729 ms 440620 KB Output is correct

Subtask #10
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 732 ms 440620 KB Output is correct

Subtask #11
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1094 ms 141176 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #12
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1074 ms 139668 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #13
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1084 ms 146224 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #14
0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 1088 ms 139548 KB Time limit exceeded
2 Halted 0 ms 0 KB -