제출 #125708

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
125708		youngyojun	Dango Maker (JOI18_dango_maker)	C++11	0 / 100	4 ms	376 KiB

dango_maker

#include <bits/stdc++.h>
#define upmax(a,b) (a)=max((a),(b))
using namespace std;

char A[3005][3005];

int D[3005][2];

int H, W, Ans;

int main() {
	scanf("%d%d", &H, &W);
	for(int i = 1; i <= H; i++) scanf(" %s", A[i]+1);

	for(int sum = 3; sum < H+W; sum++) {
		int ret = 0;
		memset(D[0], 0, 3005*2*4);
		for(int y = 1, x = sum-1; y <= H; y++, x--) {
			if(x < 1) break; if(W < x) continue;
			D[y][0] = D[y][1] = max(D[y+1][0], D[y+1][1]);
			if('G' != A[y][x]) continue;
			if('R' == A[y][x-1] && 'W' == A[y][x+1])
				upmax(D[y][0], D[y+1][0]+1);
			if('R' == A[y-1][x] && 'W' == A[y+1][x])
				upmax(D[y][1], D[y+1][1]+1);
			upmax(ret, max(D[y][0], D[y][1]));
		}
		Ans += ret;
	}

	cout << Ans << endl;
	return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

dango_maker.cpp: In function 'int main()':
dango_maker.cpp:19:4: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
    if(x < 1) break; if(W < x) continue;
    ^~
dango_maker.cpp:19:21: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
    if(x < 1) break; if(W < x) continue;
                     ^~
dango_maker.cpp:12:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &H, &W);
  ~~~~~^~~~~~~~~~~~~~~~
dango_maker.cpp:13:35: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i = 1; i <= H; i++) scanf(" %s", A[i]+1);
                              ~~~~~^~~~~~~~~~~~~~~

• Subtask 1: 0 / 13
• Subtask 2: 0 / 20
• Subtask 3: 0 / 67