이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#pragma GCC optimize("unroll-loops,no-stack-protector")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace __gnu_pbds;
using namespace std;
template <typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long ll;
typedef long double ld;
int main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
ll r,c,m;
cin >> r >> c >> m;
vector <string> grid(r);
for (int z=0;z<r;z++){
cin >> grid[z];
}
string signal;
cin >> signal;
ll dp[m+1][r][c];
for (int i=0;i<=m;i++){
for (int j=0;j<r;j++){
for (int k=0;k<c;k++){
dp[i][j][k] = 0;
}
}
}
for (int j=0;j<r;j++){
for (int k=0;k<c;k++){
if (grid[j][k] == '#') continue;
dp[0][j][k] = 1;
}
}
for (int i=1;i<=m;i++){
char now = signal[i-1];
for (int j=0;j<r;j++){
for (int k=0;k<c;k++){
if (grid[j][k] == '#') continue;
if ((now == 'W' || now == '?') && k < c-1) dp[i][j][k] += dp[i-1][j][k+1];
if ((now == 'E' || now == '?') && k > 0) dp[i][j][k] += dp[i-1][j][k-1];
if ((now == 'S' || now == '?') && j > 0) dp[i][j][k] += dp[i-1][j-1][k];
if ((now == 'N' || now == '?') && j < r-1) dp[i][j][k] += dp[i-1][j+1][k];
}
}
}
ll ans = 0;
for (int z=0;z<r;z++){
for (int x=0;x<c;x++){
if (dp[m][z][x] > 0) ans++;
}
}
cout << ans << endl;
}
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