제출 #1253056

#제출 시각아이디문제언어결과실행 시간메모리
1253056FernandoJC07장애물 (IOI25_obstacles)C++20
24 / 100
164 ms15292 KiB
#include <bits/stdc++.h>
#define For(i, a, n) for(int i = a; i<n; ++i)
#define Forr(i, a, n) for(int i = a; i>=n; --i)
#define vi vector<int>
#define vii vector<vector<int>>
using namespace std;

const int INF = 1e9+7;
vi res1, res2;

void proced(vi T, vi H, vi paabajo){
    int n = T.size();
    int m = H.size();
    vi mt(n); mt[n-1] = T[n-1]; 
    Forr(i, n-2, 0) mt[i] = max(mt[i+1], T[i]);
    vi mint(n); mint[n-1] = T[n-1];
    Forr(i, n-2, 0) mint[i] = min(mint[i+1], T[i]);
    int minx = INF;
    Forr(i, m-1, 0){
        minx = min(minx, H[i]);
        if(paabajo[i] == -1) continue;
        if(paabajo[i] == n-1){
             minx = INF;
             res2.push_back(i);
             continue;
        }
        int l = 0, r = n-1;
        while(r>l){
            int mid = l + (r-l)/2;
            if(mint[mid]<=minx) r = mid;
            else l = mid+1;
        }
        if(paabajo[i]>=l){
            res2.push_back(i);
        }
    }
    //mos(res2);
}

void initialize(vi T, vi H){
    int n = T.size();
    int m = H.size();
    vi mt(n); mt[0] = T[0]; 
    For(i, 1, n) mt[i] = max(mt[i-1], T[i]);
    vi mint(n); mint[0] = T[0];
    For(i, 1, n) mint[i] = min(mint[i-1], T[i]);
    int minx = INF;
    vi paabajo(m);
    For(i, 0, m){
        minx = min(minx, H[i]);
        int upper = upper_bound(mt.begin(), mt.end(), H[i]) - mt.begin();
        paabajo[i] = upper-1;
        --upper;
        if(upper==-1) continue;
        if(upper == n-1){
             minx = INF;
             res1.push_back(i);
             continue;
        }
        int l = 0, r = n-1;
        while(r>l){
            int mid = l + (r-l)/2;
            if(mint[mid]<=minx) r = mid;
            else l = mid+1;
        }
        if(upper>=l) res1.push_back(i);
    }
    //mos(res1);
    proced(T, H, paabajo);
    reverse(res2.begin(), res2.end());
}

bool can_reach(int L, int R, int S, int D){
    if(S>D) swap(S, D);
    auto i1 = lower_bound(res1.begin(), res1.end(), S);
    auto i2 = upper_bound(res1.begin(), res1.end(), D);
    auto i3 = lower_bound(res2.begin(), res2.end(), S);
    auto i4 = upper_bound(res2.begin(), res2.end(), D);
    return ((i1 == i2) && (i3 == i4));
}
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