제출 #1252993

#제출 시각아이디문제언어결과실행 시간메모리
1252993madamadam3세계 지도 (IOI25_worldmap)C++20
36 / 100
219 ms5008 KiB
#include "worldmap.h" #include <bits/stdc++.h> using namespace std; // #define int long long int using vi = vector<int>; using vvi = vector<vi>; void dfs(int u, vector<bool> &vis, vvi &adj, vi &tour) { vis[u] = true; tour.push_back(u); // sort(adj[u].begin(), adj[u].end(), [&](int a, int b) {return adj[a].size() < adj[b].size();}); for (int v : adj[u]) { if (vis[v]) continue; dfs(v, vis, adj, tour); tour.push_back(u); } } vvi map_from_root(int root, int n, int m, vvi &adj, vector<set<pair<int, int>>> &diags) { vector<bool> vis(n+1, false); vi tour; set<int> seen; dfs(root, vis, adj,tour); int K = 3 * n - 1; set<pair<int, int>> used; vvi ans(K, vi(K, root)), dgs(n+1); int cidx = 0; for (int i = 0; i < tour.size(); i++) { dgs[tour[i]].push_back(cidx+1); for (; cidx < 3 * i + 3; cidx++) { for (auto &el : diags[cidx]) { ans[el.first][el.second] = tour[i]; } } } for (int i = 1; i <= n; i++) { int aidx = 0; for (auto &gd : dgs[i]) { for (auto &el : diags[gd]) { if (aidx >= adj[i].size()) break; ans[el.first][el.second] = adj[i][aidx++]; } } } return ans; } bool is_valid(int n, int m, vvi &mp, vi a, vi b) { set<pair<int, int>> reqs; for (int i = 0; i < m; i++) reqs.insert({a[i], b[i]}), reqs.insert({b[i], a[i]}); int K = mp.size(); set<pair<int, int>> us; bool valid = true; for (int i = 0; i < K; i++) { for (int j = 0; j < K; j++) { if (!valid) break; if (i > 0) { valid = valid && reqs.count({mp[i-1][j], mp[i][j]}); us.insert({mp[i-1][j], mp[i][j]}); } if (j > 0) { valid = valid && reqs.count({mp[i][j-1], mp[i][j]}); us.insert({mp[i][j-1], mp[i][j]}); } if (i < K - 1) { valid = valid && reqs.count({mp[i+1][j], mp[i][j]}); us.insert({mp[i+1][j], mp[i][j]}); } if (j < K - 1) { valid = valid && reqs.count({mp[i][j+1], mp[i][j]}); us.insert({mp[i][j+1], mp[i][j]}); } } } return valid && us.size() == reqs.size(); } vvi create_map(int n, int m, vi a, vi b) { vvi adj(n+1, vi()); for (int i = 0; i < m; i++) adj[a[i]].push_back(b[i]), adj[b[i]].push_back(a[i]); int K = 3 * n - 1; vector<set<pair<int, int>>> diags(2*K-1); for (int i = 0; i < K; i++) { for (int j = 0; j < K; j++) { int md = i + j; diags[md].insert({i, j}); } } vector<int> indices(n); iota(indices.begin(), indices.end(), 1); sort(indices.begin(), indices.end(), [&](int a, int b) {return adj[a].size() < adj[b].size();}); for (auto &root : indices) { vvi mp = map_from_root(root, n, m, adj, diags); if (is_valid(n, m, mp, a, b)) { return mp; } } return map_from_root(1, n, m, adj, diags); }
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