| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1251587 | archso | 선물 (IOI25_souvenirs) | C++20 | 11 ms | 412 KiB |
#include <bits/stdc++.h>
#include "souvenirs.h"
using namespace std;
void buy_souvenirs(int n, long long p0){
int amnt = 0;
int curr = p0;
for(int i = 2; i < n; i++){
pair<vector<int>,int> stuff = transaction(curr-1);
if(stuff.first.size() == 2){
// multiple elements
// which has to be the last
amnt++;
curr--;
}
else{
// one element
curr -= (1+stuff.second);
}
for(int j = 2; j < i; j++){
transaction(curr);
}
}
// the last element has been queried a total of amnt times.
for(int i = amnt; i < n; i++){
transaction(curr-1);
}
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