제출 #125092

#제출 시각아이디문제언어결과실행 시간메모리
125092hugo_pmLong Mansion (JOI17_long_mansion)C++17
100 / 100
639 ms104996 KiB
#include <bits/stdc++.h> using namespace std; #define int long long #define form2(i, a, b) for (int i = (a); i < (b); ++i) #define ford2(i, a, b) for (int i = (a-1); i >= (b); --i) #define form(i, n) form2(i, 0, n) #define ford(i, n) ford2(i, n, 0) #define chmax(x, v) x = max(x, (v)) #define chmin(x, v) x = min(x, (v)) #define fi first #define se second const long long BIG = 1000000000000000000LL; typedef long long ll; typedef long double ld; typedef pair<int, int> pii; void solve(); signed main() { ios::sync_with_stdio(false); cin.tie(0); solve(); return 0; } // Version classique du segment tree // Opérations en O(log N) // Indices 0-indexés class SegtreeClassic { public: void init(vector<int> tab); int requete(int gauche, int droite); void modifier(int index, int val); private: const int UNDEF = 1e9 + 171; int nbElements; int combiner(int a, int b); vector<int> interne; }; void SegtreeClassic::init(vector<int> tab) { nbElements = tab.size(); interne.resize(2 * nbElements); for (int ind = 0; ind < nbElements; ++ind) interne[ind + nbElements] = tab[ind]; for (int ind = nbElements - 1; ind >= 0; --ind) interne[ind] = combiner(interne[2*ind], interne[2*ind + 1]); } int SegtreeClassic::requete(int gauche, int droite) { int res = UNDEF; ++droite; // Pour passer à un intervalle semi-ouvert [l ; r[ gauche += nbElements; droite += nbElements; while (gauche < droite) { // Si gauche est impair, le noeud est inclus mais pas le parent // On ajoute donc ce noeud et on passera plus tard au noeud à droite du parent if (gauche & 1) res = combiner(res, interne[gauche++]); // Même raisonnement sachant que droite est exclus, d'où la {pré}-décrémentation if (droite & 1) res = combiner(res, interne[--droite]); gauche /= 2; droite /= 2; } return res; } void SegtreeClassic::modifier(int index, int val) { index += nbElements; interne[index] = val; index /= 2; while (index > 0) { interne[index] = combiner(interne[2*index], interne[2*index+1]); index /= 2; } } int SegtreeClassic::combiner(int a, int b) { if (a == UNDEF) return b; if (b == UNDEF) return a; return min(a, b); } const int borne = 501*1000; int nbElem, nbReq; int reqKey[borne]; int conLeft[borne], conRight[borne]; vector<int> keyPos[borne]; vector<int> iniTab[borne]; int lastLigneDroite[borne]; int li[borne], ri[borne], gt[borne]; void solve() { cin >> nbElem; form(i, nbElem-1) { cin >> reqKey[i]; } form(iPos, nbElem) { int nbKeys; cin >> nbKeys; form(iRcp, nbKeys) { int keyId; cin >> keyId; keyPos[keyId].push_back(iPos); iniTab[iPos].push_back(keyId); } } conLeft[0] = BIG; conRight[nbElem-1] = -BIG; form(iElem, nbElem) { if (iElem > 0) { int keyToLeft = reqKey[iElem-1]; auto &listePos = keyPos[keyToLeft]; auto it = lower_bound(listePos.begin(), listePos.end(), iElem); if (listePos.empty() || it == listePos.end()) { conLeft[iElem] = BIG; } else { conLeft[iElem] = *it; } } if (iElem+1 < nbElem) { int keyToRight = reqKey[iElem]; auto &listePos = keyPos[keyToRight]; auto it = upper_bound(listePos.begin(), listePos.end(), iElem); if (listePos.empty() || it == listePos.begin()) { conRight[iElem] = -BIG; } else { --it; conRight[iElem] = *it; } } } vector<int> lstPos(borne, nbElem-1); SegtreeClassic sc; sc.init(lstPos); ford(iElem, nbElem) { if (conRight[iElem] >= 0) sc.modifier(conRight[iElem]+1, iElem); else sc.modifier(0, iElem); lastLigneDroite[iElem] = sc.requete(0, iElem); // TODO A VERIFIER } li[0] = 0; ri[0] = lastLigneDroite[0]; vector<int> tmp(borne, 0); form(i, borne) tmp[i] = -lastLigneDroite[i]; sc.init(tmp); form2(iElem, 1, nbElem) { li[iElem] = iElem; ri[iElem] = lastLigneDroite[iElem]; if (conLeft[iElem] <= ri[iElem]) { li[iElem] = li[iElem-1]; chmax(ri[iElem], ri[iElem-1]); } while (true) { if (conLeft[li[iElem]] <= ri[iElem]) { --li[iElem]; chmax(ri[iElem], gt[li[iElem]]); chmin(li[iElem], li[li[iElem]]); } else if (conRight[ri[iElem]] >= li[iElem]) { ++ri[iElem]; } else break; } sc.modifier(iElem, -ri[iElem]); gt[iElem] = -sc.requete(li[iElem], iElem); } cin >> nbReq; form(iReq, nbReq) { int x, y; cin >> x >> y; --x; --y; if (li[x] <= y && y <= ri[x]) { cout << "YES\n"; } else { cout << "NO\n"; } } }
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