Submission #1248561

#	Time	Username	Problem	Language	Result	Execution time	Memory
1248561		kaiboy	Adriatic (CEOI13_adriatic)	C++20	100 / 100	252 ms	126244 KiB

adriatic

#include <algorithm>
#include <iostream>

using namespace std;

const int K = 250000;
const int N = 2500;

int ii[K], jj[K], aa[N][N], pp[N][N], qq[N][N], ii_[N], jj_[N], xx[N][N], yy[N][N];

int main() {
	ios_base::sync_with_stdio(false), cin.tie(NULL);
	int k; cin >> k;
	for (int h = 0; h < k; h++) {
		int i, j; cin >> i >> j, i--, j--;
		ii[h] = i, jj[h] = j;
		aa[i][j] = pp[i][j] = qq[i][j] = 1;
	}
	for (int i = 1; i < N; i++)
		for (int j = 0; j < N; j++)
			pp[i][j] += pp[i - 1][j];
	for (int i = 0; i < N; i++)
		for (int j = N - 2; j >= 0; j--)
			pp[i][j] += pp[i][j + 1];
	for (int i = N - 2; i >= 0; i--)
		for (int j = 0; j < N; j++)
			qq[i][j] += qq[i + 1][j];
	for (int i = 0; i < N; i++)
		for (int j = 1; j < N; j++)
			qq[i][j] += qq[i][j - 1];
	for (int j = 0; j < N; j++) {
		int i_ = j ? ii_[j - 1] : N;
		for (int i = 0; i < N; i++)
			if (aa[i][j])
				i_ = min(i_, i);
		ii_[j] = i_;
	}
	for (int i = N - 1; i >= 0; i--) {
		int j_ = i + 1 < N ? jj_[i + 1] : -1;
		for (int j = 0; j < N; j++)
			if (aa[i][j])
				j_ = max(j_, j);
		jj_[i] = j_;
	}
	for (int i = 0; i < N; i++)
		for (int j = N - 1; j >= 0; j--)
			if (pp[i][j]) {
				int i_ = j ? min(ii_[j - 1], i) : i;
				int j_ = i + 1 < N ? max(jj_[i + 1], j) : j;
				xx[i][j] = pp[i][j] + xx[i_][j_];
			}
	for (int j = N - 1; j >= 0; j--) {
		int i_ = j + 1 < N ? ii_[j + 1] : -1;
		for (int i = 0; i < N; i++)
			if (aa[i][j])
				i_ = max(i_, i);
		ii_[j] = i_;
	}
	for (int i = 0; i < N; i++) {
		int j_ = i ? jj_[i - 1] : N;
		for (int j = 0; j < N; j++)
			if (aa[i][j])
				j_ = min(j_, j);
		jj_[i] = j_;
	}
	for (int i = N - 1; i >= 0; i--)
		for (int j = 0; j < N; j++)
			if (qq[i][j]) {
				int i_ = j + 1 < N ? max(ii_[j + 1], i) : i;
				int j_ = i ? min(jj_[i - 1], j) : j;
				yy[i][j] = qq[i][j] + yy[i_][j_];
			}
	for (int h = 0; h < k; h++) {
		int i = ii[h], j = jj[h];
		cout << xx[i][j] + yy[i][j] + k - 3 << '\n';
	}
	return 0;
}

• Subtask 1: 25 / 25
• Subtask 2: 25 / 25
• Subtask 3: 10 / 10
• Subtask 4: 20 / 20
• Subtask 5: 20 / 20