제출 #1243861

#제출 시각아이디문제언어결과실행 시간메모리
1243861AlperenT_나일강 (IOI24_nile)C++20
67 / 100
2094 ms5360 KiB
#include "nile.h"
#include <bits/stdc++.h> 
#pragma GCC optimize("O3,unroll-loops") 
#pragma GCC target("avx2") 
#define pb push_back
#define F first
#define pii pair<int,int> 
#define all(a) a.begin(),a.end()
#define S second 
#define sz(a) (int)a.size()
#define rep(i , a , b) for(int i = (a) ; i <= (b) ; i++)
#define per(i , a , b) for(int i = (a) ; i >= (b) ; i--)
#define ld double
#define ll long long 
using namespace std ;
const int maxn = 1e6 + 100 , inf = 1e9 , mod = 998244353;
ll dp[maxn] ;
std::vector<long long> calculate_costs(std::vector<int> W, std::vector<int> A,std::vector<int> B, std::vector<int> E) {
  int n =  sz(W) ;
  ll sm =0 ;
  vector <pii> vec; 
  rep(i , 0 ,n-1){
    vec.pb({W[i] , A[i]-B[i]}) ; 
    sm += A[i]; 
  }
  sort(all(vec));
  vector <ll> ans ;
  for(int d : E){
    ll mx= 0 ;
    rep(i ,0 , n-1){
      dp[i] = dp[i-1] ;
      per(j ,i-1, 0){
        if(vec[i].F - vec[j].F  <= d){
          dp[i] = max(dp[i] , dp[j-1] + vec[i].S + vec[j].S) ;
        }
        if(j == i-2)break ;
      }
      mx= max(mx ,dp[i]);
    }
    ans.pb(sm-mx);
  }
  return ans;
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...