제출 #1243279

#제출 시각아이디문제언어결과실행 시간메모리
1243279Zbyszek99디지털 회로 (IOI22_circuit)C++20
100 / 100
344 ms41664 KiB
#include "circuit.h"
#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define ull unsigned long long
#define ff first
#define ss second
#define pii pair<int,int>
#define pll pair<long long, long long>
#define vi vector<int>
#define vl vector<long long>
#define pb push_back
#define rep(i, b) for(int i = 0; i < (b); ++i)
#define rep2(i,a,b) for(int i = a; i <= (b); ++i)
#define rep3(i,a,b,c) for(int i = a; i <= (b); i+=c)
#define count_bits(x) __builtin_popcountll((x))
#define all(x) (x).begin(),(x).end()
#define siz(x) (int)(x).size()
#define forall(it,x) for(auto& it:(x))
using namespace std;
const int INF = 1e9+50;
const ll INF_L = 1e18+40;
const ll MOD = 1000002022;

const int tree_siz = 1024*512-1;
ll sum[tree_siz+1];
ll rev_sum[tree_siz+1];
int oper[tree_siz+1];

void spych(int v)
{
    if(oper[v])
    {
        swap(sum[v*2],rev_sum[v*2]);
        swap(sum[v*2+1],rev_sum[v*2+1]);
        oper[v*2] ^= 1;
        oper[v*2+1] ^= 1;
        oper[v] = 0;
    }
}

void change_seg(int akt, int p1, int p2, int s1, int s2)
{
    if(p2 < s1 || p1 > s2) return;
    if(p1 >= s1 && p2 <= s2)
    {
        swap(sum[akt],rev_sum[akt]);
        oper[akt] ^= 1;
        return;
    }
    spych(akt);
    change_seg(akt*2,p1,(p1+p2)/2,s1,s2);
    change_seg(akt*2+1,(p1+p2)/2+1,p2,s1,s2);
    sum[akt] = sum[akt*2] + sum[akt*2+1];
    sum[akt] %= MOD;
    rev_sum[akt] = rev_sum[akt*2] + rev_sum[akt*2+1];
    rev_sum[akt] %= MOD;
}

vi graph[200001];
ll ways[200001];
ll ans_ways[200001];
int n;

void dfs(ll v)
{
    ways[v] = max(1,siz(graph[v]));
    forall(it,graph[v])
    {
        dfs(it);
        ways[v] *= ways[it];
        ways[v] %= MOD;
    }
}

void dfs_ans(int v, ll w)
{
    ans_ways[v] = w;
    vl pref(siz(graph[v]));
    vl suf(siz(graph[v]));
    ll cur = 1;
    rep(i,siz(graph[v]))
    {
        cur *= ways[graph[v][i]];
        cur %= MOD;
        pref[i] = cur;
    }
    cur = 1;
    for(int i = siz(graph[v])-1; i >= 0; i--)
    {
        cur *= ways[graph[v][i]];
        cur %= MOD;
        suf[i] = cur;
    }
    rep(i,siz(graph[v]))
    {
        ll w2 = w;
        if(i != 0)
        {
            w2 *= pref[i-1];
            w2 %= MOD;
        }
        if(i != siz(graph[v])-1)
        {
            w2 *= suf[i+1];
            w2 %= MOD;
        }
        dfs_ans(graph[v][i],w2);
    }
}

void init(int N, int M, vi P, vi A) 
{
    n = N;
    rep(i,N+M) if(P[i] != -1) graph[P[i]].pb(i);
    dfs(0);
    dfs_ans(0,1);
    rep2(i,tree_siz/2+1,tree_siz/2+M)
    {
        int v = N + i - (tree_siz/2+1);
        if(A[v-N] == 1) sum[i] = ans_ways[v];
        else rev_sum[i] = ans_ways[v];
    }
    for(int i = tree_siz/2; i >= 1; i--)
    {
        sum[i] = (sum[i*2]+sum[i*2+1]) % MOD;
        rev_sum[i] = (rev_sum[i*2]+rev_sum[i*2+1]) % MOD;
    }
}

int count_ways(int L, int R) 
{
    change_seg(1,0,tree_siz/2,L-n,R-n);
    return sum[1];
}
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