제출 #1243109

#제출 시각아이디문제언어결과실행 시간메모리
1243109KindaGoodGames말 (IOI15_horses)C++20
34 / 100
1596 ms20388 KiB
#include<bits/stdc++.h>
#include "horses.h"

using namespace std;
#define pii pair<int,int>
#define int long long

int mod = 1e9+7;

struct SegmentTree{
	int len = 1;
	vector<int> S;
	SegmentTree(){}
	SegmentTree(int n){
		while(len < n) len <<= 1;
		S.resize(2*len, 1);
	}

	int query(int ql, int qr, int l= 0, int r = -2, int i = 1){
		if(r == -2) r = len;
		if(ql <= l && r <= qr) return S[i];
		if(r <= ql || qr <= l) return 1;

		int mid = (l+r)/2;
		return (query(ql,qr,l,mid,i*2) * query(ql,qr,mid,r,i*2+1)) % mod;
	}

	void upd(int i, int v){
		i += len;
		S[i] = v;

		for(i /= 2; i > 0; i /= 2){
			S[i] = (S[i*2] * S[i*2+1])% mod;
		}
	}
};
int n;

vector<int> X;
vector<int> Y;
SegmentTree seg;
int32_t init(int32_t N, int32_t mult[], int32_t cost[]) {
	n = N;
	X.resize(n);
	Y.resize(n);
	seg = SegmentTree(n);
	for(int i = 0; i < n; i++){
		X[i] = mult[i];
		Y[i] = cost[i];
	} 
	for(int i = 0;i < n; i++){
		seg.upd(i, X[i]);
	} 

	int cur = 1;

	for(int i = 0; i < n; i++){
		cur *= X[i];
		cur %= mod;
		int c = 1;
		bool valid = false;
		for(int j = i+1; j < n; j++){
			c *= X[j];

			if(c > Y[i] || c *Y[j] > Y[i]){
				valid = true;
				break;
			}
		}

		if(!valid){ 
			return (cur * Y[i])% mod;
		}
	}  
	return (cur*Y[n-1])%mod;
}

int32_t updateX(int32_t pos, int32_t val) {	
	X[pos] = val;

	int cur = 1;

	for(int i = 0; i < n; i++){
		cur *= X[i];
		cur %= mod;
		int c = 1;
		bool valid = false;
		for(int j = i+1; j < n; j++){
			c *= X[j];

			if(c > Y[i] || c *Y[j] > Y[i]){
				valid = true;
				break;
			}
		}

		if(!valid){ 
			return (cur * Y[i])% mod;
		}
	}  
	return (cur*Y[n-1])%mod;
}

int32_t updateY(int32_t pos, int32_t val) {
	Y[pos] = val;

	int cur = 1;

	for(int i = 0; i < n; i++){
		cur *= X[i];
		cur %= mod;
		int c = 1;
		bool valid = false;
		for(int j = i+1; j < n; j++){
			c *= X[j];

			if(c > Y[i] || c *Y[j] > Y[i]){
				valid = true;
				break;
			}
		}

		if(!valid){ 
			return (cur * Y[i])% mod;
		}
	}  
	return (cur*Y[n-1])%mod;
}
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