Submission #1242909

#TimeUsernameProblemLanguageResultExecution timeMemory
1242909tvgk코알라 (JOI13_koala)C++20
100 / 100
66 ms4548 KiB
#include<bits/stdc++.h>
using namespace std;
#define task "a"
#define se second
#define fi first
#define ll long long
#define ii pair<ll, ll>
const long mxN = 1e5 + 7;
const ll inf = 1e18 + 7;

vector<int> val;
ii a[mxN];
ll tree[mxN * 4];

void Build(int j = 1, int l = 0, int r = val.size() - 1)
{
    tree[j] = -inf;
    if (l == r)
        return;

    int mid = (l + r) / 2;
    Build(j * 2, l, mid);
    Build(j * 2 + 1, mid + 1, r);
}

void Upd(int u, int v, ll nw, int j = 1, int l = 0, int r = val.size() - 1)
{
    if (u > val[r] || val[l] > v)
        return;

    if (u <= val[l] && val[r] <= v)
    {
        tree[j] = max(tree[j], nw);
        return;
    }

    int mid = (l + r) / 2;
    Upd(u, v, nw, j * 2, l, mid);
    Upd(u, v, nw, j * 2 + 1, mid + 1, r);
}

ll Get(int vt, int j = 1, int l = 0, int r = val.size() - 1)
{
    if (val[l] > vt || vt > val[r])
        return -inf;

    if (l == r)
        return tree[j];

    int mid = (l + r) / 2;
    return max({Get(vt, j * 2, l, mid), Get(vt, j * 2 + 1, mid + 1, r), tree[j]});
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    //freopen(task".INP", "r", stdin);
    //freopen(task".OUT", "w", stdout);

    int l, r, mx, n;
    ll cost;
    cin >> l >> r >> mx >> cost >> n;
    for (int i = 1; i <= n; i++)
        cin >> a[i].fi >> a[i].se;
    a[0].fi = l;
    a[n + 1].fi = r;

    n++;
    for (int i = 0; i <= n; i++)
        val.push_back(a[i].fi % mx);
    sort(val.begin(), val.end());
    val.erase(unique(val.begin(), val.end()),val.end());
    Build();

    for (int i = 0; i < n; i++)
    {
        ll dp = Get(a[i].fi % mx) - a[i].fi / mx * cost;
        if (!i)
            dp = 0;
        dp += a[i].se;

        Upd(0, a[i].fi % mx, dp + (a[i].fi / mx) * cost);
        Upd(a[i].fi % mx + 1, mx - 1, dp + (a[i].fi / mx - 1) * cost);
    }
    cout << Get(a[n].fi % mx) - a[n].fi / mx * cost;
}

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