제출 #1242150

#제출 시각아이디문제언어결과실행 시간메모리
1242150M_SH_OConstruction Project 2 (JOI24_ho_t2)C++20
100 / 100
457 ms32772 KiB
/*#pragma GCC optimize("O3") #pragma GCC optimization("Ofast,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")*/ #include <bits/stdc++.h> /*#include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp>*/ #define ll long long #define ll1 long long #define ull unsigned long long #define dou long double #define str string #define vll vector<ll> #define vi vector<int> #define pll pair<ll, ll> #define vpll vector<pll> #define vbool vector<bool> #define vstr vector<str> #define vvll vector<vll> #define pb push_back #define pf push_front #define endl "\n" #define fr first #define se second // #define sortcmp(a) sort(a.begin(), a.end(), cmp) #define sort(a) sort(a.begin(), a.end()) #define reverse(a) reverse(a.begin(), a.end()) #define speed ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0) #define INF 1000000000000000007 #define ordered_set tree<ll, null_type, less_equal<ll>, rb_tree_tag, tree_order_statistics_node_update> using namespace std; //using namespace __gnu_pbds; mt19937 rng(time(0)); ll randll(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rng); } vector<vpll> g; void dijkstra(ll n, vll& d, vector<vpll>& g1) { set<pll> s; for (int i = 1; i <= n; i ++) { s.insert({d[i], i}); } while (s.size()) { pll p = *s.begin(); s.erase(s.begin()); for (auto i : g1[p.se]) { if (p.fr+i.se < d[i.fr]) { s.erase({d[i.fr], i.fr}); d[i.fr] = p.fr+i.se; s.insert({d[i.fr], i.fr}); } } } } int main(){ speed; srand(time(0)); ll n, m; cin >> n >> m; ll a, b, l, k; cin >> a >> b >> l >> k; g.resize(n+7); for (int i =0 ; i < m; i ++) { ll a, b, c; cin >> a >> b >> c; g[a].pb({b, c}); g[b].pb({a, c}); } vll d(n+7, INF); d[a] = 0; dijkstra(n, d, g); if (d[b] <= k) { cout << n*(n-1)/2 << endl; return 0; } vll d_ = d; sort(d); vll d1(n+7, INF); d1[b] = 0; dijkstra(n, d1, g); ll res = 0; for (int i = 1; i <= n; i ++) { ll l1 = -1, r1 = n; while (r1-l1 > 1) { ll x = (l1+r1)/2; if (d[x]+l+d1[i] > k) r1 = x; else l1 = x; } res += l1+1; if (d1[i]+l+d_[i] <= k) res --; } cout << res << endl; }
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