Submission #1241766

#TimeUsernameProblemLanguageResultExecution timeMemory
1241766BahaminBuilding Bridges (CEOI17_building)C++20
100 / 100
38 ms7748 KiB
#include <bits/stdc++.h> using namespace std; template<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << ", " << p.second << ')'; } template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> ostream& operator<<(ostream &os, const T_container &v) { os << '{'; string sep; for (const T &x : v) os << sep << x, sep = ", "; return os << '}'; } #define ll long long #define ld long double #define all(a) (a).begin(), (a).end() #define sui cout.tie(NULL); cin.tie(NULL); ios_base::sync_with_stdio(false) const int MAX_N = 1e5 + 5; const int MOD = 1e9 + 7; const ll INF = 1e18; const ld EPS = 1e-9; const int LOG = 30; inline ll divf(ll a, ll b) { assert(b); return a/b - ((a^b)<0 && a%b); } struct line { mutable ll m, c, p; bool operator<(const line &l) const { return m < l.m; } bool operator<(ll x) const { return p < x; } }; struct cht : multiset<line, less<>> { private: inline ll isect(iterator x, iterator y) { return divf(x->c-y->c, y->m-x->m); } public: inline void add(ll m, ll c) { auto y = insert({m, c, INF}), x = y++; if(empty()) return; if(y!=end() && x->m==y->m) { if(x->c<=y->c) { erase(x); return; } y = erase(y); } if(x!=begin() && prev(x)->m==x->m) { if(x->c<=prev(x)->c) { erase(x); return; } erase(prev(x)); } if(x!=begin() && y!=end() && isect(x, y)<=prev(x)->p) { erase(x); return; } while(y!=end()) { ll p = isect(x, y); if(p>=y->p) y = erase(y); else { x->p = p; break; } } if(x==begin()) return; y = x--; while(x!=begin() && isect(prev(x), y)<=prev(x)->p) { erase(x); x = prev(y); } x->p = isect(x, y); } inline ll get(ll x) { assert(!empty()); auto it = lower_bound(x); return it->m*x + it->c; } }; cht lines; void solve() { int n; cin >> n; int h[n]; for (int i = 0; i < n; i++) cin >> h[i]; int w[n]; for (int i = 0; i < n; i++) cin >> w[i]; ll dp[n]; dp[0] = 0; lines.add(2 * h[0], w[0] - 1ll * h[0] * h[0]); ll sum = w[0]; for (int i = 1; i < n; i++) { dp[i] = sum + 1ll * h[i] * h[i] - lines.get(h[i]); sum += w[i]; lines.add(2 * h[i], -dp[i] + sum - 1ll * h[i] * h[i]); } cout << dp[n - 1] << "\n"; } int main() { sui; int tc = 1; //cin >> tc; for (int t = 1; t <= tc; t++) { solve(); } }
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