제출 #1240782

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1240782		dosts	Closing Time (IOI23_closing)	C++20	21 / 100	1097 ms	25712 KiB

closing

#include "closing.h"
#include <bits/stdc++.h>
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2")
#define int long long
#define pii pair<int,int>
#define vi vector<int>
#define ff first
#define ss second
#define sp << " " <<
#define all(x) x.begin(),x.end()
#define big(x) ((int)(x.size()))
using namespace std;
const int MOD = 1e9+7, LIM = 2e5+1, inf = 2e18;

vector<pii> edges[LIM];
vi distX(LIM),distY(LIM);
void dfs(int node,int p,int flag,int cur) {
    if (!flag) distX[node] = cur;
    else distY[node] = cur;
    for (auto it : edges[node]) {
        if (it.ff == p) continue;
        dfs(it.ff,node,flag,cur+it.ss);
    }
}

signed max_score(signed N, signed X, signed Y, int K,
              std::vector<signed> U, std::vector<signed> V, std::vector<signed> W)
{
    if (X > Y) swap(X,Y);
    for (int i = 0;i<N;i++) edges[i].clear();
    int M = big(U);
    for (int i = 0;i<M;i++) { 
        edges[U[i]].push_back({V[i],W[i]});
        edges[V[i]].push_back({U[i],W[i]});
    }
    dfs(X,X,0,0),dfs(Y,Y,1,0);
    int ansy = 0;
    for (signed L = 0;L<N;L++) {
        for (signed R = L;R < N;R++) {
            if (R < X || L > Y) continue;
            int k =K;
            int ans = 0;
            int fl = 1;
            for (signed j = min(L,X);j<=max(Y,R);j++) {
                int cost;
                 if (j >= L && j <= R) cost =  max(distX[j],distY[j]);
                 else if (j < L) cost = distX[j];
                 else cost = distY[j];
                int contr = (j >= L && j <= R) ? 2 : 1;
                if (cost > k) {
                    fl = 0;
                    break;
                }
                k-=cost;
                ans+=contr;
            }
            priority_queue<pii,vector<pii>,greater<pii>> pq;
            if (min(L,X)) pq.push({distX[min(L,X)-1],min(L,X)-1});
            if (max(Y,R)<N-1) pq.push({distY[max(Y,R)+1],max(Y,R)+1});
            while (!pq.empty()) {
                auto [cost,place] = pq.top();
                pq.pop();
                if (cost > k) break;
                k-=cost;
                ans++;
                if (place < min(L,X) && place) {
                    pq.push({distX[place-1],place-1});
                }
                if (place > max(R,Y) && place < N-1) {
                    pq.push({distY[place+1],place+1});
                }
            }
            if (fl) ansy = max(ansy,ans);
            //cout << L sp R sp ans << endl;
        }
    }
    for (int i=X;i<Y;i++) {
        priority_queue<pii,vector<pii>,greater<pii>> pq;
        pq.push({distX[X],X});
        pq.push({distY[Y],Y});
        int ans = 0;
        int k = K;
        while (!pq.empty()) {
            auto [cost,place] = pq.top();
            pq.pop();
            if (cost > k) break;
            k-=cost;
            ans++;
            if (place <= i) {
                if (place < i && place >= X) {
                    pq.push({distX[place+1],place+1});
                }
                if (place <= X && place) {
                    pq.push({distX[place-1],place-1});
                }
            }
            else {
                if (place > i+1 && place <= Y) {
                    pq.push({distY[place-1],place-1});
                }
                if (place != N-1 && place >= Y) {
                    pq.push({distY[place+1],place+1});
                }
            }
        }
        //cout << i sp ans << endl;
        ansy = max(ansy,ans);
    }
    return ansy;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 8
• Subtask 2: 9 / 9
• Subtask 3: 12 / 12
• Subtask 4: 0 / 14
• Subtask 5: 0 / 9
• Subtask 6: 0 / 11
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 17