Submission #1239330

#	Time	Username	Problem	Language	Result	Execution time	Memory
1239330		matsakyannn	수천개의 섬 (IOI22_islands)	C++20	8.40 / 100	24 ms	13640 KiB

islands

#include <bits/stdc++.h>
#include <variant>
using namespace std;

#ifndef ONLINE_JUDGE
#define dbg(x) cerr << #x << ' '; print(x); cerr << endl;
#else
#define dbg(x)
#endif 

void print(int x) {cerr << x;}
void print(long long x) {cerr << x;}
void print(char x) {cerr << x;}
void print(string x) {cerr << x;}
void print(double x) {cerr << x;}
template <class T> void print(vector <T> x);
template <class T> void print(set <T> x);
template <class T> void print(multiset <T> x);
template <class T, class V> void print(pair <T, V> x);
template <class T, class V> void print(map <T, V> x);
template <class T> void print(vector <T> x) {cerr << "[ "; for(auto i : x) {print(i); cerr << ' ';} cerr << "]";}
template <class T> void print(set <T> x) {cerr << "[ "; for(auto i : x) {print(i); cerr << ' ';} cerr << "]";}
template <class T> void print(multiset <T> x) {cerr << "[ "; for(auto i : x) {print(i); cerr << ' ';} cerr << "]";}
template <class T, class V> void print(pair <T, V> x) {cerr << "{"; print(x.first); cerr << ' '; print(x.second); cerr << "}";}
template <class T, class V> void print(map <T, V> x) {cerr << "[ "; for(auto i : x) {print(i); cerr << ' ';} cerr << "]";}

#define ll long long
#define pb push_back
#define ppb pop_back
#define PII pair <int, int>
#define PLL pair <ll, ll>
#define all(v) (v).begin(), (v).end()
#define OK cerr << "OK\n";
#define MP make_pair

const int N0 = 1005, M0 = 2e5 + 5;
int n, m;
PII kayak[N0][N0];
vector <int> u, v;
vector <int> G[N0];

vector <int> cycle, road;
int par[N0];
int color[N0];
bool dfs(int node){
    bool cycle = 0;
    color[node] = 1;
    for(int u : G[node]){
        if(color[u] == 1) cycle = 1;
        else if(color[u] == 0) cycle |= dfs(u);
    }
    color[node] = 2;
    return cycle;
}

variant <bool, vector <int>> find_journey(int N, int M, vector<int> U, vector<int> V){
    n = N, m = M, u = U, v = V;
    for(int i = 0; i < M; i += 2){
        G[u[i]].pb(v[i]);
        kayak[u[i]][v[i]] = {i, i + 1};
    }

    return dfs(0);
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 5
• Subtask 3: 0 / 21
• Subtask 4: 8.4 / 24
• Subtask 5: 0 / 45