제출 #1237679

#제출 시각아이디문제언어결과실행 시간메모리
1237679bangan모자이크 (IOI24_mosaic)C++20
7 / 100
101 ms19192 KiB
#include "mosaic.h"
#include <bits/stdc++.h>
#include <vector>
using namespace std;

#define ll long long

#define pb push_back

#define LC (v<<1)
#define RC (v<<1|1)
#define mid ((l+r) >> 1)

std::vector<long long> mosaic(std::vector<int> X, std::vector<int> Y, std::vector<int> T, std::vector<int> B, std::vector<int> lo, std::vector<int> hi) {
	int n = X.size();
	int q = (int)T.size();
    if (n==1) return vector<ll> (q, X[0]);

    vector<ll> ans(q);
    vector<int> all(q);
    iota(all.begin(), all.end(), 0);
    sort(all.begin(), all.end(), [&](int i, int j) {
        return T[i]<T[j];
    });
    auto it = all.begin();

    vector<ll> a;
    for (int i=1; i<n; i++) a.pb(X[i]);
    for (int i = n-2; 0<=i; i--) a[i] += a[i+1];

    auto get = [&](int l, int r) {
        if (r+1 == a.size()) return a[l];
        return a[l] - a[r+1];
    };

    for (int r=0; r<2; r++) {
        while (it!=all.end() && T[*it]==r) {
            int L = lo[*it];
            int R = hi[*it];
            if (L==0) ans[*it] = Y[r], L++;
            L--, R--;
            if (L<=R) ans[*it] += get(L, R);
            it++;
        }

        if (r+1 != n) {
            vector<ll> b;
            b.pb((Y[r+1]|get(0, 0))^1);
            for (int i=1; i<a.size(); i++) b.pb((b.back()|get(i, i))^1);
            swap(a, b);
            for (int i = n-2; 0<=i; i--) a[i] += a[i+1];
        }
    }

    {
        vector<ll> b = a;
        a.clear();
        for (int i=0; i<n; i++) a.pb(0);
        for (int i:b) a.pb(i);
    }
    int z=n;

    for (int r=2; r<n; r++) {
        while (it!=all.end() && T[*it]==r) {
            int L = lo[*it];
            int R = hi[*it];
            if (L==0) ans[*it] = Y[r], L++;
            L--, R--;
            if (L<=R) ans[*it] += get(z+L, z+R);
            it++;
        }
        
        if (r+1 != n) {
            z--;
            int t = (Y[r+1]|a[z+1])^1;
            if (z+2 < a.size()) a[z+1] = ((get(z+2, z+2)|t) ^ 1) + a[z+2];
            a[z] = t + a[z+1];
        }
    }
    return ans;
}
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