제출 #1235692

#제출 시각아이디문제언어결과실행 시간메모리
1235692iamhereforfunRobot (JOI21_ho_t4)C++20
0 / 100
3093 ms44284 KiB
// IamHereForFun // #include <bits/stdc++.h> using namespace std; #define LSOne(X) ((X) & -(X)) const int N = 1e5 + 5; const int M = 11; const int L = 12; const int LG = 25; const int P = 37; const long long INF = 1e18 + 5; const int MOD = 1e9 + 7; const int nx[] = {0, -1, 0, 1}, ny[] = {-1, 0, 1, 0}; // find shortest path, for every node, calculate minimum path // problemo: because everytime you change an edge, it affects the next node too =)) // lets say you change a edge, then you should change it so that it doesn't affect the next one =)) // but if you change a edge for another edge to be valid, then you shouldn't go to the node that it's connect too, other wise just use it // so we use dp[N] as normal, but in your pq, you save a number indicating that the edge that leads to it is changed or not int n, m; vector<array<int, 3>> adj[N]; vector<int> id[N]; vector<long long> dp[N]; vector<bool> vis[N]; long long ans = 0; int gid(int a, int b) { return lower_bound(id[a].begin(), id[a].end(), b) - id[a].begin(); } void solve() { cin >> n >> m; for (int x = 1; x <= n; x++) { id[x].push_back(-1); } for (int x = 0; x < m; x++) { int a, b, c, p; cin >> a >> b >> c >> p; adj[a].push_back({b, c, p}); adj[b].push_back({a, c, p}); id[a].push_back(b); id[b].push_back(a); } for(int x = 1; x <= n; x++) { sort(id[x].begin(), id[x].end()); vis[x].assign(id[x].size(), 0); dp[x].assign(id[x].size(), INF); } priority_queue<array<long long, 3>> pq; dp[1][0] = 0; pq.push({0, -1, 1}); while (!pq.empty()) { array<long long, 3> arr = pq.top(); pq.pop(); int i = arr[2], l = arr[1]; l = gid(i, l); if (vis[i][l]) continue; vis[i][l] = true; map<int, long long> mp; for (array<int, 3> a : adj[i]) { if (a[0] == l) continue; mp[a[1]] += a[2]; } for (array<int, 3> a : adj[i]) { if (a[0] == l) continue; long long val = mp[a[1]] - a[2]; int j = a[0], cid = gid(j, i); if (dp[j][cid] > dp[i][l] + a[2]) { dp[j][cid] = dp[i][l] + a[2]; pq.push({-dp[j][cid], i, j}); } cid = 0; if (dp[j][cid] > dp[i][l] + val) { dp[j][cid] = dp[i][l] + val; pq.push({-dp[j][cid], -1, j}); } } } ans = INF; for(long long i : dp[n]) ans = min(ans, i); if (ans == INF) { cout << -1 << "\n"; } else { cout << ans << "\n"; } } signed main() { ios_base::sync_with_stdio(0); cin.tie(0); int t = 1; // cin >> t; for (int x = 1; x <= t; x++) { solve(); } return 0; }
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