제출 #1234586

#제출 시각아이디문제언어결과실행 시간메모리
1234586rxlfd314메기 농장 (IOI22_fish)C++20
0 / 100
992 ms2162688 KiB
#include "fish.h" #include <bits/stdc++.h> using namespace std; using ll = long long; using ari2 = array<int, 2>; using ari3 = array<int, 3>; using arl2 = array<ll, 2>; using arl3 = array<ll, 3>; template <class T> using vt = vector<T>; #define all(x) begin(x), end(x) #define size(x) (int((x).size())) #define REP(a,b,c,d) for(int a=(b);(d)>0?a<=(c):a>=(c);a+=(d)) #define FOR(a,b,c) REP(a,b,c,1) #define ROF(a,b,c) REP(a,b,c,-1) constexpr ll INF = 1e18; ll max_weights(int N, int M, vt<int> X, vt<int> Y, vt<int> W) { vt<vt<ll>> P(N+1, vt<ll>(N+1)); FOR(i, 0, M-1) { X[i]++, Y[i]++; P[X[i]][Y[i]] = W[i]; } FOR(i, 1, N) FOR(j, 1, N) P[i][j] += P[i][j-1]; vt<vt<arl2>> dp(N+1, vt<arl2>(N+1, {-INF, -INF})); dp[0][0][0] = dp[0][0][1] = 0; ll ans = 0; FOR(i, 1, N) FOR(j, 0, N) { FOR(k, 0, j) dp[i][j][0] = max(dp[i][j][0], (i > 1 ? max(dp[i-2][k][0], dp[i-2][k][1]) : 0) + P[i-1][j]); FOR(k, j+1, N) dp[i][j][0] = max(dp[i][j][0], (i > 1 ? max(dp[i-2][k][0], dp[i-2][k][1]) : 0) + P[i-1][k]); dp[i][j][1] = dp[i][j][0]; FOR(k, 0, j) dp[i][j][0] = max(dp[i][j][0], dp[i-1][k][0] + P[i-1][j] - P[i-1][k]); FOR(k, j, N) dp[i][j][1] = max(dp[i][j][1], dp[i-1][k][1] + P[i][k] - P[i][j]); ans = max({ans, dp[i][j][0], dp[i][j][1]}); FOR(k, 0, N) ans = max(ans, max(dp[i-1][k][0], dp[i-1][k][1]) + P[i][k]); } return ans; }
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