이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<stdio.h>
#include<vector>
#include<algorithm>
using namespace std;
#define MAXN 200005
const int INF = 1 << 30;
int N, Q;
int H[MAXN], A[MAXN], B[MAXN], L[MAXN], R[MAXN];
int ans[MAXN];
int minc[4*MAXN], maxd[4*MAXN], lazy[4*MAXN];
vector<int> query[MAXN], on[2*MAXN], off[2*MAXN];
void spreadlazy(int idx) {
if(lazy[idx] != -1) {
lazy[idx * 2] = lazy[idx * 2 + 1] = lazy[idx];
maxd[idx * 2] = max(maxd[idx * 2], lazy[idx] - minc[idx * 2]);
maxd[idx * 2 + 1] = max(maxd[idx * 2 + 1], lazy[idx] - minc[idx * 2 + 1]);
lazy[idx] = -1;
}
}
void updc(int idx, int l, int r, int x, int c) {
//if(idx == 1) printf("updc(x = %d, c = %d)\n", x, c);
if(l == r) {
minc[idx] = c;
if(lazy[idx] != -1) maxd[idx] = max(maxd[idx], lazy[idx] - c);
return;
}
spreadlazy(idx);
int m = (l + r) / 2;
if(x <= m) updc(idx * 2, l, m, x, c);
else updc(idx * 2 + 1, m + 1, r, x, c);
minc[idx] = min(minc[idx * 2], minc[idx * 2 + 1]);
maxd[idx] = max(maxd[idx * 2], maxd[idx * 2 + 1]);
}
void updlazy(int idx, int l, int r, int x, int y, int z) {
//if(idx == 1) printf("updlazy(x = %d, y = %d, z = %d)\n", x, y, z);
if(x <= l && r <= y) {
lazy[idx] = z;
maxd[idx] = max(maxd[idx], z - minc[idx]);
return;
}
if(r < x || y < l) return;
spreadlazy(idx);
int m = (l + r) / 2;
updlazy(idx * 2, l, m, x, y, z);
updlazy(idx * 2 + 1, m + 1, r, x, y, z);
maxd[idx] = max(maxd[idx * 2], maxd[idx * 2 + 1]);
}
int gmaxd(int idx, int l, int r, int x, int y) {
if(x <= l && r <= y) return maxd[idx];
if(r < x || y < l) return -1;
int m = (l + r) / 2;
spreadlazy(idx);
return max(gmaxd(idx * 2, l, m, x, y), gmaxd(idx * 2 + 1, m + 1, r, x, y));
}
void print(int x){
printf("#%d\n", x);
for(int i = 1; i < 10; i++)
printf("i = %d, maxd = %d, minc = %d, lazy = %d\n", i, maxd[i], minc[i], lazy[i]);
for(int i = 0; i < Q; i++) printf("ans[%d] = %d\n", i, ans[i]);
printf("\n");
}
void solve() {
for(int i = 0; i < 2 * N; i++) {
query[i].clear();
on[i].clear();
off[i].clear();
}
for(int i = 0; i < Q; i++) query[R[i]].push_back(i);
for(int i = 0; i < N; i++) {
on[i + A[i]].push_back(i);
off[i + B[i]].push_back(i);
}
for(int i = 1; i < 4 * N; i++) {
minc[i] = INF;
maxd[i] = lazy[i] = -1;
}
for(int i = 0; i < N; i++) {
for(auto a : on[i]) updc(1, 0, N-1, a, H[a]);
//print(1);
updlazy(1, 0, N-1, i - B[i], i - A[i], H[i]);
//print(2);
for(auto a : query[i]) ans[a] = max(ans[a], gmaxd(1, 0, N-1, L[a], i));
//print(3);
for(auto a : off[i]) updc(1, 0, N-1, a, INF);
//print(4);
}
}
int main() {
scanf("%d", &N);
for(int i = 0; i < N; i++) scanf("%d%d%d", H+i, A+i, B+i);
scanf("%d", &Q);
for(int i = 0; i < Q; i++) scanf("%d%d", L+i, R+i);
for(int i = 0; i < Q; i++) {
ans[i] = -INF;
L[i]--;
R[i]--;
}
solve();
for(int i = 0; i < N/2; i++){
swap(H[i], H[N - i - 1]);
swap(A[i], A[N - i - 1]);
swap(B[i], B[N - i - 1]);
}
for(int i = 0; i < Q; i++) {
swap(L[i], R[i]);
L[i] = N - L[i] - 1;
R[i] = N - R[i] - 1;
}
solve();
for(int i = 0; i < Q; i++) printf("%d\n", ans[i]);
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
antennas.cpp: In function 'int main()':
antennas.cpp:101:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d", &N);
~~~~~^~~~~~~~~~
antennas.cpp:102:34: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
for(int i = 0; i < N; i++) scanf("%d%d%d", H+i, A+i, B+i);
~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
antennas.cpp:103:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d", &Q);
~~~~~^~~~~~~~~~
antennas.cpp:104:34: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
for(int i = 0; i < Q; i++) scanf("%d%d", L+i, R+i);
~~~~~^~~~~~~~~~~~~~~~~~
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