Submission #1233640

#	Time	Username	Problem	Language	Result	Execution time	Memory
1233640		SpyrosAliv	Art Collections (BOI22_art)	C++20	20 / 100	54 ms	408 KiB

art

#include "art.h"
#include <bits/stdc++.h>
using namespace std;
//
// --- Sample implementation for the task art ---
//
// To compile this program with the sample grader, place:
//     art.h art_sample.cpp sample_grader.cpp
// in a single folder, then open the terminal in this directory (right-click onto an empty spot in the directory,
// left click on "Open in terminal") and enter e.g.:
//     g++ -std=c++17 art_sample.cpp sample_grader.cpp
// in this folder. This will create a file a.out in the current directory which you can execute from the terminal
// as ./a.out
// See task statement or sample_grader.cpp for the input specification
//

int n;
vector<int> p;

bool smaller(int a, int b) {
    vector<int> perm;
    perm.push_back(a);
    perm.push_back(b);
    for (int i = 1; i <= n; i++) {
        if (i != a && i != b) perm.push_back(i);
    }
    int tot = publish(perm);
    swap(perm[0], perm[1]);
    int tot2 = publish(perm);
    if (tot2 > tot) {
        return 1;
    }
    else return 0;
}

void merge(int l, int r) {
    if (l == r) return;
    int mid = (l + r) / 2;
    merge(l, mid);
    merge(mid+1, r);
    vector<int> a, b;
    for (int i = l; i <= mid; i++) a.push_back(p[i]);
    for (int i = mid+1; i <= r; i++) b.push_back(p[i]);
    vector<int> fin;
    int pa = 0, pb = 0;
    while (pa < (int)a.size() && pb < (int)b.size()) {
        if (smaller(a[pa], b[pb])) {
            fin.push_back(a[pa]);
            pa++;
        }
        else {
            fin.push_back(b[pb]);
            pb++;
        }
    }
    while (pa < (int)a.size()) {
        fin.push_back(a[pa]);
        pa++;
    }
    while (pb < (int)b.size()) {
        fin.push_back(b[pb]);
        pb++;
    }
    for (int i = l; i <= r; i++) {
        p[i] = fin[i - l];
    }
}

void solve(int N) {
    n = N;
    for (int i = 1; i <= n; i++) p.push_back(i);
    sort(p.begin(), p.end(), [&](int a, int b) {
        return smaller(a, b);
    });
    answer(p);
}

• Subtask 1: 5 / 5
• Subtask 2: 15 / 15
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30