| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 1232986 | LaMatematica14 | Star Trek (CEOI20_startrek) | C++20 | 0 ms | 324 KiB |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long N, D; cin >> N >> D;
vector<vector<int>> adj(N+1); // occhio 1-based
for (int i = 0; i < N-1; i++) {
int u, v; cin >> u >> v;
adj[u].push_back(v);
adj[v].push_back(u);
}
vector<int> w(N+1, 0); // 0 for loosing
function<void(int,int)> dfs = [&](int a, int p) {
for (int x : adj[a]) {
if (x == p) continue;
dfs(x, a);
if (w[x] == 0) w[a] = 1;
}
};
dfs(1, 0);
cout << w[1] << "\n";
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