답안 #123265

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
123265 2019-06-30T23:56:03 Z duality Coin Collecting (JOI19_ho_t4) C++11
0 / 100
1000 ms 376 KB
#define DEBUG 0

#include <bits/stdc++.h>
using namespace std;

#if DEBUG
// basic debugging macros
int __i__,__j__;
#define printLine(l) for(__i__=0;__i__<l;__i__++){cout<<"-";}cout<<endl
#define printLine2(l,c) for(__i__=0;__i__<l;__i__++){cout<<c;}cout<<endl
#define printVar(n) cout<<#n<<": "<<n<<endl
#define printArr(a,l) cout<<#a<<": ";for(__i__=0;__i__<l;__i__++){cout<<a[__i__]<<" ";}cout<<endl
#define print2dArr(a,r,c) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<a[__i__][__j__]<<" ";}cout<<endl;}
#define print2dArr2(a,r,c,l) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<setw(l)<<setfill(' ')<<a[__i__][__j__]<<" ";}cout<<endl;}

// advanced debugging class
// debug 1,2,'A',"test";
class _Debug {
    public:
        template<typename T>
        _Debug& operator,(T val) {
            cout << val << endl;
            return *this;
        }
};
#define debug _Debug(),
#else
#define printLine(l)
#define printLine2(l,c)
#define printVar(n)
#define printArr(a,l)
#define print2dArr(a,r,c)
#define print2dArr2(a,r,c,l)
#define debug
#endif

// define
#define MAX_VAL 999999999
#define MAX_VAL_2 999999999999999999LL
#define EPS 1e-6
#define mp make_pair
#define pb push_back

// typedef
typedef unsigned int UI;
typedef long long int LLI;
typedef unsigned long long int ULLI;
typedef unsigned short int US;
typedef pair<int,int> pii;
typedef pair<LLI,LLI> plli;
typedef vector<int> vi;
typedef vector<LLI> vlli;
typedef vector<pii> vpii;
typedef vector<plli> vplli;

// ---------- END OF TEMPLATE ----------

int X[200000],Y[200000];
pii p[200000];
vpii in[2];
int diff[100000][2];
int main() {
    int i;
    int N;
    LLI ans = 0;
    scanf("%d",&N);
    for (i = 0; i < 2*N; i++) {
        scanf("%d %d",&X[i],&Y[i]);
        //X[i] = rand(),Y[i] = rand();
        //X[i] = (rand() % N)+1,Y[i] = ((rand() % 2)+1);
        if (X[i] < 1) ans += 1-X[i],X[i] = 1;
        if (X[i] > N) ans += X[i]-N,X[i] = N;
        if (Y[i] < 1) ans += 1-Y[i],Y[i] = 1;
        if (Y[i] > 2) ans += Y[i]-2,Y[i] = 2;
        p[i] = mp(X[i],Y[i]);
        diff[X[i]-1][Y[i]-1]++;
    }
    sort(p,p+2*N);

    int j;
    LLI temp = ans;
    for (i = 0; i < 2*N; i++) {
        int x = i/2+1,y = (i % 2)+1;
        ans += abs(p[i].first-x)+abs(p[i].second-y);
        if (p[i].second != y) {
            y--;
            pii a = mp(x,p[i].first);
            int m = 0;
            for (j = 0; j < in[y].size(); j++) {
                if (abs(in[y][j].first-in[y][j].second)+abs(a.first-a.second)+2 > \
                    abs(in[y][j].first-a.second)+abs(a.first-in[y][j].second)) {

                    m = max(m,abs(in[y][j].first-in[y][j].second)+abs(a.first-a.second)+2-abs(in[y][j].first-a.second)-abs(a.first-in[y][j].second));
                }
            }
            if (m > 0) {
                for (j = 0; j < in[y].size(); j++) {
                    if (abs(in[y][j].first-in[y][j].second)+abs(a.first-a.second)+2- \
                        abs(in[y][j].first-a.second)-abs(a.first-in[y][j].second) == m) {

                        ans -= m;
                        break;
                    }
                }
                for (j++; j < in[y].size(); j++) in[y][j-1] = in[y][j];
                in[y].pop_back();
            }
            else in[!y].pb(a);
        }
        //cout<<"ans: "<<ans<<endl;
        //for (j=0;j<in[0].size();j++)cout<<0<<" "<<in[0][j].first<<","<<in[0][j].second<<endl;
        //for (j=0;j<in[1].size();j++)cout<<1<<" "<<in[1][j].first<<","<<in[1][j].second<<endl;
    }
    vpii a,b;
    for (i = 0; i < N; i++) {
        diff[i][0]--,diff[i][1]--;
        if (diff[i][0] > 0) a.pb(mp(i,0));
        else if (diff[i][0] < 0) b.pb(mp(i,0));
        if (diff[i][1] > 0) a.pb(mp(i,1));
        else if (diff[i][1] < 0) b.pb(mp(i,1));
    }
    sort(b.begin(),b.end());
    do {
        LLI x = temp;
        for (i = 0; i < a.size(); i++) x += abs(a[i].first-b[i].first)+abs(a[i].second-b[i].second);
        if (x < ans) ans = x;
    } while (next_permutation(b.begin(),b.end()));
    printf("%lld\n",ans);

    return 0;
}

Compilation message

joi2019_ho_t4.cpp: In function 'int main()':
joi2019_ho_t4.cpp:89:27: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
             for (j = 0; j < in[y].size(); j++) {
                         ~~^~~~~~~~~~~~~~
joi2019_ho_t4.cpp:97:31: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
                 for (j = 0; j < in[y].size(); j++) {
                             ~~^~~~~~~~~~~~~~
joi2019_ho_t4.cpp:105:29: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
                 for (j++; j < in[y].size(); j++) in[y][j-1] = in[y][j];
                           ~~^~~~~~~~~~~~~~
joi2019_ho_t4.cpp:125:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
         for (i = 0; i < a.size(); i++) x += abs(a[i].first-b[i].first)+abs(a[i].second-b[i].second);
                     ~~^~~~~~~~~~
joi2019_ho_t4.cpp:66:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d",&N);
     ~~~~~^~~~~~~~~
joi2019_ho_t4.cpp:68:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d %d",&X[i],&Y[i]);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Execution timed out 1066 ms 256 KB Time limit exceeded
6 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Execution timed out 1066 ms 256 KB Time limit exceeded
6 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 376 KB Output is correct
2 Correct 2 ms 376 KB Output is correct
3 Correct 2 ms 376 KB Output is correct
4 Correct 2 ms 376 KB Output is correct
5 Execution timed out 1066 ms 256 KB Time limit exceeded
6 Halted 0 ms 0 KB -