| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 1231189 | PVM_pvm | COVID tests (CEOI24_covid) | C++20 | 7054 ms | 408 KiB | 
#include<bits/stdc++.h>
using namespace std;
#define MAXN 1007
/// You may use:
// The number of students
int N;
// The probability any given student is positive
double P;
// This function performs a test on a subset of samples.
// Its argument is a vector of Booleans of length N,
// where the i-th element is true if the i-th sample should be added to the mix.
// It returns true if (and only if) at least one of the samples in the mix is positive.
bool test_students(vector<bool> mask) {
    assert(mask.size() == (size_t)N);
    string mask_str(N, ' ');
    for (int i = 0; i < N; i++)
        mask_str[i] = mask[i] ? '1' : '0';
    printf("Q %s\n", mask_str.c_str());
    fflush(stdout);
    char answer;
    scanf(" %c", &answer);
    return answer == 'P';
}
/// You should implement:
// This function will be called once for each test instance.
// It should use test_students to determine which samples are positive.
// It must return a vector of Booleans of length N,
// where the i-th element is true if and only if the i-th sample is positive.
bool otgov[MAXN];
void findd(int l, int r)
{
    vector<bool> nl(N,0);
    for (int q=l;q<=r;q++) nl[q]=1;
    bool otg=test_students(nl);
    if (otg)
    {
        if (l==r)
        {
            otgov[l]=1;
            return;
        }
        int mid=(l+r)/2;
        findd(l,mid);
        findd(mid+1,r);
    }
}
vector<bool> find_positive() {
    int klk=1.0/P;
        vector<bool> answer(N,0);
        for (int cq=0;cq<N;cq+=klk)
        {
            vector<bool> nl3(N,0);
            for (int w=cq;w<min(cq+klk,N);w++) nl3[w]=1;
            bool toi=test_students(nl3);
            if (!toi) continue;
            int lr=cq,rr=min(cq+klk-1,N-1);
            while (true)
            {
                vector<bool> nl(N,0);
                for (int q=lr;q<=rr;q++) nl[q]=1;
                bool otg;
                if (rr-lr+1==klk || (rr!=N-1 && lr!=cq)) otg=1;
                else otg=test_students(nl);
                if (otg==0) break;
                int l=lr-1,r=rr;
                while (l<r-1)
                {
                    int mid=(l+r)/2;
                    vector<bool> nl2(N,0);
                    for (int q=lr;q<=mid;q++) nl2[q]=1;
                    otg=test_students(nl2);
                    if (otg) r=mid;
                    else l=mid;
                }
                answer[r]=1;
                lr=r+1;
            }
        }
        return answer;
}
int main() {
    int T;
    scanf("%d %lf %d", &N, &P, &T);
    // You may perform any extra initialization here.
    for (int i = 0; i < T; i++) {
        vector<bool> answer = find_positive();
        assert(answer.size() == (size_t)N);
        string answer_str(N, ' ');
        for (int j = 0; j < N; j++)
            answer_str[j] = answer[j] ? '1' : '0';
        printf("A %s\n", answer_str.c_str());
        fflush(stdout);
        char verdict;
        scanf(" %c", &verdict);
        if (verdict == 'W')
            exit(0);
    }
    return 0;
}
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