제출 #122876

#제출 시각아이디문제언어결과실행 시간메모리
122876egorlifarSkyscraper (JOI16_skyscraper)C++17
100 / 100
250 ms19188 KiB
/*
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 */
#include <iostream>
#include <complex>
#include <vector>
#include <string>
#include <algorithm>
#include <cstdio>
#include <numeric>
#include <cstring>
#include <ctime>
#include <cstdlib>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <list>
#include <cmath>
#include <bitset>
#include <cassert>
#include <queue>
#include <stack>
#include <deque>
    
     
using namespace std;
template<typename T1, typename T2>inline void chkmin(T1 &x, T2 y) { if (x > y) x = y; }
template<typename T1, typename T2>inline void chkmax(T1 &x, T2 y) { if (x < y) x = y; } 
template<typename T, typename U> inline ostream &operator<< (ostream &_out, const pair<T, U> &_p) { _out << _p.first << ' ' << _p.second; return _out; }
template<typename T, typename U> inline istream &operator>> (istream &_in, pair<T, U> &_p) { _in >> _p.first >> _p.second; return _in; }
template<typename T> inline ostream &operator<< (ostream &_out, const vector<T> &_v) { if (_v.empty()) { return _out; } _out << _v.front(); for (auto _it = ++_v.begin(); _it != _v.end(); ++_it) { _out << ' ' << *_it; } return _out; }
template<typename T> inline istream &operator>> (istream &_in, vector<T> &_v) { for (auto &_i : _v) { _in >> _i; } return _in; }
template<typename T> inline ostream &operator<< (ostream &_out, const set<T> &_s) { if (_s.empty()) { return _out; } _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) { _out << ' ' << *_it; } return _out; }
template<typename T> inline ostream &operator<< (ostream &_out, const multiset<T> &_s) { if (_s.empty()) { return _out; } _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) { _out << ' ' << *_it; } return _out; }
template<typename T> inline ostream &operator<< (ostream &_out, const unordered_set<T> &_s) { if (_s.empty()) { return _out; } _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) { _out << ' ' << *_it; } return _out; }
template<typename T> inline ostream &operator<< (ostream &_out, const unordered_multiset<T> &_s) { if (_s.empty()) { return _out; } _out << *_s.begin(); for (auto _it = ++_s.begin(); _it != _s.end(); ++_it) { _out << ' ' << *_it; } return _out; }
template<typename T, typename U> inline ostream &operator<< (ostream &_out, const map<T, U> &_m) { if (_m.empty()) { return _out; } _out << '(' << _m.begin()->first << ": " << _m.begin()->second << ')'; for (auto _it = ++_m.begin(); _it != _m.end(); ++_it) { _out << ", (" << _it->first << ": " << _it->second << ')'; } return _out; }
template<typename T, typename U> inline ostream &operator<< (ostream &_out, const unordered_map<T, U> &_m) { if (_m.empty()) { return _out; } _out << '(' << _m.begin()->first << ": " << _m.begin()->second << ')'; for (auto _it = ++_m.begin(); _it != _m.end(); ++_it) { _out << ", (" << _it->first << ": " << _it->second << ')'; } return _out; }
#define sz(c) (int)(c).size()
#define all(c) (c).begin(), (c).end()
#define rall(c) (c).rbegin(), (c).rend()
#define left left228
#define right right228
#define next next228
#define rank rank228
#define prev prev228
#define y1 y1228                                                         
#define read(FILENAME) freopen((FILENAME + ".in").c_str(), "r", stdin)
#define write(FILENAME) freopen((FILENAME + ".out").c_str(), "w", stdout)
#define files(FILENAME) read(FILENAME), write(FILENAME)
#define pb push_back
const string FILENAME = "input";
const int MAXN = 101;
const int Mod = 1000000007;


int sum(int a, int b) {
	return (a + b >= Mod ? a + b - Mod: a + b);
}


int mul(int a, int b) {
	return (1LL * a * b) % Mod;
}

int n, m;
int a[MAXN];
int dp[MAXN][MAXN][1001][2][2];


int main() {
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	//read(FILENAME);
	cin >> n >> m;
	for (int i = 0; i < n; i++) {
		cin >> a[i];
	}
	if (n == 1) {
		cout << 1 << endl;
		return 0;
	}
	sort(a, a + n);
	for (int i = n - 1; i >= 1; i--) {
		a[i] -= a[i - 1];
	}
	a[0] = 0;
	dp[0][0][0][0][0] = 1;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j <= i; j++) {
			for (int k = 0; k <= m; k++) {
				for (int l = 0; l < 2; l++) {
					for (int r = 0; r < 2; r++) {
						int cnt = dp[i][j][k][l][r];
						if (!cnt) continue;
						int nk = k + a[i] * (2 * j - l - r);
						if (nk > m) {
							continue;
						}
						if (!l) {
							int mult = j - r;
							if (i == n - 1) {
								mult += r;
							}
							dp[i + 1][j][nk][1][r] = sum(dp[i + 1][j][nk][1][r], mul(mult, cnt));
							dp[i + 1][j + 1][nk][1][r] = sum(dp[i + 1][j + 1][nk][1][r], cnt);
						}
						if (!r) {
							int mult = j - l;
							if (i == n - 1) {
								mult += l;
							}
							dp[i + 1][j][nk][l][1] = sum(dp[i + 1][j][nk][l][1], mul(mult, cnt));
							dp[i + 1][j + 1][nk][l][1] = sum(dp[i + 1][j + 1][nk][l][1], cnt);
						}
						dp[i + 1][j][nk][l][r] = sum(dp[i + 1][j][nk][l][r], mul(cnt, 2 * j - l - r));
						dp[i + 1][j + 1][nk][l][r] = sum(dp[i + 1][j + 1][nk][l][r], cnt);
						if (j > 1) {
							int mult = (j - l - r) * (j - 1);
							if (i == n - 1) {
								mult += (l & r);
							}
							dp[i + 1][j - 1][nk][l][r] = sum(dp[i + 1][j - 1][nk][l][r], mul(mult, cnt));
						}
					}
				}
 			}
		}
	} 
	int ans = 0;
	for (int i = 0; i <= m; i++) {
		ans = sum(ans, dp[n][1][i][1][1]);
	}
	cout << ans << endl;
	return 0; 		
}
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