제출 #1227231

#제출 시각아이디문제언어결과실행 시간메모리
1227231HishamAlshehriLongest beautiful sequence (IZhO17_subsequence)C++20
23 / 100
379 ms327680 KiB
#include <bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
 
using namespace std;
// using namespace __gnu_pbds;
 
#define int long long
#define mod 1000000007
#define base 7001
#define base2 757
#define F first
#define S second
// #define pi acos(-1)
#define double long double
// #define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update>
// #define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>

// #pragma GCC optimize("O3,Ofast,unroll-loops")
// #pragma GCC target("avx2,sse3,sse4,avx")

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

constexpr int maxn = 1000005;
const int N = 1 << (int)(ceil(log2(maxn)));

int n, a[maxn], k[maxn], ans[maxn], par[maxn], dp[maxn];

// pair<int, int> q(int take, int bit, int i, int x) {
//     if (!take) return dp[x];
//     if (bit == 8) return 0;

//     pair<int, int> ret = {0, -1};
//     if (a[i] & (1ll << bit)) ret = max(q(take - 1, bit + 1, i, x ^ (1ll << bit)), ret);
//     else ret = max(ret, q(take, bit + 1, i, x));

//     return;
// }

// void u(int take, int bit, int i, int x) {
//     if (!take) dp[x] = max(dp[x], make_pair(ans[i], i));
//     if (bit == 8) return;

//     if (a[i] & (1ll << bit)) u(take - 1, bit + 1, i, x ^ (1ll << bit));
//     else u(take, bit + 1, i, x);

//     return;
// }

signed main()
{
    cin.tie(0) -> sync_with_stdio(0);
    cin >> n;

    // for (int i = 0; i < maxn; i++) dp[i] = {0, -1};
    for (int i = 0; i < n; i++) cin >> a[i];
    for (int i = 0; i < n; i++) cin >> k[i];

    for (int i = 0; i < n; i++) {
        pair<int, int> mx = {0, -1};
        if (n <= 5e3) {
            for (int j = 0; j < i; j++) {
                if (__builtin_popcount(a[i] & a[j]) == k[i]) mx = max(make_pair(ans[j], j), mx);
            }
            ans[i] = mx.F + 1;
            par[i] = mx.S;
        }
        // else {
        //     auto x = q(k[i])
        // }
    }

    pair<int, int> mx = {0, -1};
    for (int i = 0; i < n; i++) mx = max(mx, make_pair(ans[i], i));

    vector<int> v;
    cout << mx.F << '\n';
    int cur = mx.S;
    while (cur != -1) {
        v.push_back(cur);
        cur = par[cur];
    }
    reverse(v.begin(), v.end());

    for (int i : v) cout << i + 1 << ' ';
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...