Submission #1227231

#TimeUsernameProblemLanguageResultExecution timeMemory
1227231HishamAlshehriLongest beautiful sequence (IZhO17_subsequence)C++20
23 / 100
379 ms327680 KiB
#include <bits/stdc++.h> // #include <ext/pb_ds/assoc_container.hpp> // #include <ext/pb_ds/tree_policy.hpp> using namespace std; // using namespace __gnu_pbds; #define int long long #define mod 1000000007 #define base 7001 #define base2 757 #define F first #define S second // #define pi acos(-1) #define double long double // #define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> // #define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update> // #pragma GCC optimize("O3,Ofast,unroll-loops") // #pragma GCC target("avx2,sse3,sse4,avx") mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); constexpr int maxn = 1000005; const int N = 1 << (int)(ceil(log2(maxn))); int n, a[maxn], k[maxn], ans[maxn], par[maxn], dp[maxn]; // pair<int, int> q(int take, int bit, int i, int x) { // if (!take) return dp[x]; // if (bit == 8) return 0; // pair<int, int> ret = {0, -1}; // if (a[i] & (1ll << bit)) ret = max(q(take - 1, bit + 1, i, x ^ (1ll << bit)), ret); // else ret = max(ret, q(take, bit + 1, i, x)); // return; // } // void u(int take, int bit, int i, int x) { // if (!take) dp[x] = max(dp[x], make_pair(ans[i], i)); // if (bit == 8) return; // if (a[i] & (1ll << bit)) u(take - 1, bit + 1, i, x ^ (1ll << bit)); // else u(take, bit + 1, i, x); // return; // } signed main() { cin.tie(0) -> sync_with_stdio(0); cin >> n; // for (int i = 0; i < maxn; i++) dp[i] = {0, -1}; for (int i = 0; i < n; i++) cin >> a[i]; for (int i = 0; i < n; i++) cin >> k[i]; for (int i = 0; i < n; i++) { pair<int, int> mx = {0, -1}; if (n <= 5e3) { for (int j = 0; j < i; j++) { if (__builtin_popcount(a[i] & a[j]) == k[i]) mx = max(make_pair(ans[j], j), mx); } ans[i] = mx.F + 1; par[i] = mx.S; } // else { // auto x = q(k[i]) // } } pair<int, int> mx = {0, -1}; for (int i = 0; i < n; i++) mx = max(mx, make_pair(ans[i], i)); vector<int> v; cout << mx.F << '\n'; int cur = mx.S; while (cur != -1) { v.push_back(cur); cur = par[cur]; } reverse(v.begin(), v.end()); for (int i : v) cout << i + 1 << ' '; }
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