#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int MOD = 1e9 + 7;
int add (int a, int b) {
a += b; if (a >= MOD) a -= MOD;
return a;
}
int sub (int a, int b) {
a -= b; if (a < 0) a += MOD;
return a;
}
int mul (int a, int b) {
return (a * 1ll * b) % MOD;
}
int power (int a, int b) {
if (!b) return 1;
int u = power(a, b >> 1);
u = mul(u, u);
if (b & 1) u = mul(u, a);
return u;
}
const int N = 5000;
int fact[N + 1], inv[N + 1];
int nCr (int a, int b) {
return mul(fact[a], mul(inv[b], inv[a - b]));
}
int dp[N + 1][N + 1];
void solve () {
fact[0] = 1;
for (int i = 1; i <= N; i++) {
fact[i] = mul(i, fact[i - 1]);
}
inv[N] = power(fact[N], MOD - 2);
for (int i = N - 1; i >= 0; i--) {
inv[i] = mul(i + 1, inv[i + 1]);
}
for (int i = 0; i <= N; i++) {
dp[0][i] = 1;
}
for (int i = 1; i <= N; i++) {
dp[i][0] = 1;
for (int j = 1; j <= N; j++) {
dp[i][j] = add(dp[i][j], dp[i - 1][j]);
dp[i][j] = add(dp[i][j], mul(4 * j, dp[i - 1][j - 1]));
if (i >= 2) {
dp[i][j] = add(dp[i][j], mul(j * (i - 1), dp[i - 2][j - 1]));
}
if (j >= 2) {
dp[i][j] = add(dp[i][j], mul(j * (j - 1) / 2, dp[i - 1][j - 2]));
}
}
}
int x, y; cin >> x >> y;
cout << sub(dp[x][y], 1) << '\n';
}
signed main () {
ios::sync_with_stdio(0); cin.tie(0);
int tc = 1; //cin >> tc;
while (tc--) solve();
}
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