제출 #1222227

#제출 시각아이디문제언어결과실행 시간메모리
1222227countlessGap (APIO16_gap)C++20
30 / 100
41 ms2912 KiB
#include "gap.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; const ll MOD = 998244353; const ll INF = 1e18; const ld EPS = 1e-12; #define endl "\n" #define sp <<" "<< #define REP(i, a, b) for(ll i = a; i < b; i++) #define dbg(x) cout << #x << " = " << x << endl #define mp make_pair #define pb push_back #define fi first #define se second #define fast_io() ios_base::sync_with_stdio(false); cin.tie(NULL) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define sz(x) ((ll)(x).size()) struct custom_hash { static uint64_t splitmix64(uint64_t x) { // http://xorshift.di.unimi.it/splitmix64.c x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; template <typename Key, typename Value> using hash_map = unordered_map<Key, Value, custom_hash>; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); // uniform_int_distribution<int>(a, b)(rng); // shuffle(all(a), rng); ll findGap(int T, int N) { if (T == 1) { ll a = 0, b = 1e18; vector<ll> nums; while ((int)nums.size() < N) { ll c, d; MinMax(a, b, &c, &d); nums.push_back(c); if (c != d) nums.push_back(d); a = c + 1; b = d - 1; } sort(all(nums)); ll ans = LLONG_MIN; REP(i, 1, N) ans = max(ans, nums[i] - nums[i-1]); return ans; } else if (T == 2) { vector<ll> nums; vector<pair<ll, ll>> ranges, nranges, cranges; ll lb, ub; MinMax(0, 1e18, &lb, &ub); ll len = (ub - lb + N - 2) / (N - 1); ll ans = 0, run = lb; vector<ll> lbs, ubs; ubs.push_back(lb); REP(i, 0, N - 1) { ll a = lb + i * len, b = min(ub, a + len - 1); ll x, y; MinMax(a, b, &x, &y); if (x != -1 and y != -1) { lbs.push_back(x); ubs.push_back(y); } } lbs.push_back(ub); assert(lbs.size() == ubs.size()); ll N = lbs.size(); REP(i, 0, N) { ans = max(ans, lbs[i] - ubs[i]); } return ans; } return 0; }
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