#include <iostream>
#include <vector>
#include <set>
#include <iomanip>
#include <algorithm>
#include <functional>
#include <stdio.h>
#include <cmath>
#include <queue>
#include <string>
#include <map>
#include <fstream>
#include <complex>
#include <random>
#include <stack>
#include <chrono>
#include <set>
#define FOR(i,n) for(int i=0;i<n;i++)
#define FORE(i,a,b) for(int i=a;i<=b;i++)
#define ll long long int
#define vi vector<int>
#define ii pair<int,int>
#define pb push_back
#define mp make_pair
#define ff first
#define ss second
#define pll pair<ll,ll>
#define cd complex<double>
#define ld long double
#define pld pair<ld,ld>
#define iii pair<ii,int>
#define vv vector
using namespace std;
const int MAXN = 5e5+10;
int C[MAXN];
int leftNeeded[MAXN];
int rightNeeded[MAXN];
vi keys[MAXN];
int L[MAXN];
int R[MAXN];
int last[MAXN];
#define endl '\n'
int main(){
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
FOR(i,n-1)cin >> C[i];
FOR(i,n){
int x;cin >> x;
FOR(j,x){
int y;cin >> y;
keys[i].pb(y);
}
}
// input taking is done, now find left and right needed values for each edge.
FOR(i,MAXN)last[i] = -1;
FOR(i,n-1){
for(auto e : keys[i]){
last[e] = i;
}
leftNeeded[i] = last[C[i]];
}
FOR(i,MAXN)last[i] = n;
for(int i = n-1;i>0;i--){
for(auto e : keys[i])last[e] = i;
rightNeeded[i-1] = last[C[i-1]];
}
FOR(i,n-1){
// cout << leftNeeded[i] << " " << rightNeeded[i] << endl;
}
// we have found out the left and right needed. now we need to compute all the ranges.
FOR(i,n){
int rightl = (i == 0)?-1:R[i-1];
if(rightl >= i){
// we know that we cannot escape from this box anyway.
// now try to go left once.
int minR = R[i-1];
int ind = -1;
FORE(edge,i,minR-1){
if(leftNeeded[edge] < i){
ind = edge;
}
}
if(ind == -1){
L[i] = L[i-1];
R[i] = R[i-1];
}else{
L[i] = i;
R[i] = ind;
}
}else{
// try increasing right ptr one by one. and for each such move, increase left pointer as much as possible.
int lptr = i;
int rptr = i;
while(rptr < n){
while(lptr > 0 and rightNeeded[lptr-1] <= rptr)lptr--;
if(leftNeeded[rptr] < lptr)break;
rptr++;
}
L[i] = lptr;
R[i] = rptr;
}
// cout << L[i] << " " << R[i] << endl;
}
int q;
cin >> q;
//cout << q << endl;
FOR(i,q){
int x,y;
cin >> x >> y;
x--;y--;
if(L[x] <= y and y <= R[x]){
cout << "YES" << endl;
}else{
cout << "NO" << endl;
}
}
return 0;
}
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
16 ms |
14208 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
16 ms |
14208 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
868 ms |
28852 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
16 ms |
14208 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
