제출 #1221094

#제출 시각아이디문제언어결과실행 시간메모리
1221094madamadam3Commuter Pass (JOI18_commuter_pass)C++20
0 / 100
2095 ms17452 KiB
#include <bits/stdc++.h> using namespace std; #define int long long int using pi = pair<int, int>; using vb = vector<bool>; using vi = vector<int>; using vvi = vector<vi>; using vpi = vector<pi>; using vvpi = vector<vpi>; const int MAXN = 100'001, MAXM = 200'001; const int INF = numeric_limits<int>::max(); int n, m, X[MAXM], Y[MAXM], C[MAXM]; int S, T, U, V; vi adj[MAXN]; void dijkstra(int u, vi &dist, vi &par) { dist.assign(n+1, INF); par.assign(n+1, -1); dist[u] = 0; par[u] = 0; priority_queue<pi, vector<pi>, greater<pi>> q; q.push({0, u}); while (!q.empty()) { auto cur = q.top(); q.pop(); int cu = cur.second, cdist = cur.first; for (auto &el : adj[cu]) { int cv = X[el] == cu ? Y[el] : X[el]; int vdist = C[el]; if(dist[cu] + vdist < dist[cv]) { par[cv] = cu; dist[cv] = dist[cu] + vdist; q.push({dist[cu] + vdist, cv}); } } } } void dfs(int u, int last_edge, int cur_dist, int shortest, vb &seen, vvi &paths, vi &par) { if (cur_dist > shortest) return; if (cur_dist == shortest && u == T) { vi path; int cur = last_edge; while (cur != -1) { path.push_back(cur); cur = par[cur]; } paths.push_back(path); return; } seen[u] = true; for (auto &eid : adj[u]) { int v = X[eid] == u ? Y[eid] : X[eid]; int d = C[eid]; if (seen[v]) continue; par[eid] = last_edge; dfs(v, eid, cur_dist + d, shortest, seen, paths, par); par[eid] = -1; } seen[u] = false; } signed main() { cin >> n >> m; cin >> S >> T >> U >> V; for (int i = 1; i <= m; i++) { cin >> X[i] >> Y[i] >> C[i]; adj[X[i]].push_back(i); adj[Y[i]].push_back(i); } vi sd, spar; dijkstra(S, sd, spar); int shortest = sd[T]; vvi paths; vb seen(n+1, false); vi par(m+1, -1); dfs(S, -1, 0, shortest, seen, paths, par); int best = INF; for (auto &path : paths) { vi prev_val(path.size()); for (int i = 0; i < path.size(); i++) { prev_val[i] = C[path[i]]; C[path[i]] = 0; } vi ud, upar; dijkstra(U, ud, upar); best = min(best, ud[V]); for (int i = 0; i < path.size(); i++) { C[path[i]] = prev_val[i]; } } cout << best; return 0; }
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