제출 #1217891

#제출 시각아이디문제언어결과실행 시간메모리
1217891qwusha축구 경기장 (IOI23_soccer)C++20
8 / 100
4594 ms412 KiB
#include <bits/stdc++.h>
#include "soccer.h"
using namespace std;
#define fi first
#define se second
typedef long long ll;
typedef long double ld;
mt19937 rnd(chrono::high_resolution_clock::now().time_since_epoch().count());
ll inf = 1e18;

bool all_good(int n, vector<vector<int>> f) {
    bool ok = 1;
    int cnt = 0;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n; j++) {
            if (f[i][j] == 0) {
                cnt++;
            }
        }
    }
    for (int vi = 0; vi < n; vi++) {
        for (int vj = 0; vj < n; vj++) {
            for (int ui = 0; ui < n; ui++) {
                for (int uj = 0; uj < n; uj++) {
                    if (!(f[vi][vj] == 0 && f[ui][uj] == 0))
                        continue;
                    int mini = min(vi, ui);
                    int maxi = max(vi, ui);
                    int minj = min(vj, uj);
                    int maxj = max(vj, uj);
                    bool fii = 1, fij = 1;
                    for (int i = mini; i <= maxi; i++) {
                        if (f[i][vj] == 1)
                            fii = 0;
                        if (f[i][uj] == 1)
                            fij = 0;
                    }
                    for (int j = minj; j <= maxj; j++) {
                        if (f[ui][j] == 1)
                            fii = 0;
                        if (f[vi][j] == 1) {
                            fij = 0;
                        }
                    }
                    if (fii == 0 && fij == 0) {
                        ok = 0;
                    }
                }
            }
        }
    }
    return ok;
}


int biggest_stadium(int n, vector<vector<int>> f) {
    int res = 0;
    for (int ma = 0; ma < (1 << (n * n)); ma++) {
        vector<vector<int>> vec(n, vector<int>(n));
        bool valid = 1;
        int num = 0;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n; j++) {
                if ((ma >> (i * n + j)) & 1) {
                    vec[i][j] = 0;
                    num++;
                } else {
                    vec[i][j] = 1;
                }
                if (vec[i][j] == 0 && f[i][j] == 1) {
                    valid = 0;
                }
            }
        }
        if (!valid) {
            continue;
        }
        if (all_good(n, vec)) {
            res = max(res, num);
        }
    }
    return res;
}
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