제출 #1217375

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1217375		rkgena	Palembang Bridges (APIO15_bridge)	C++20	22 / 100	78 ms	14696 KiB

bridge

#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define IOS ios::sync_with_stdio(0); cin.tie(0);
#define lli long long int
#define pb push_back
#define all(x) x.begin(),x.end()
#define rep(i,a,b) for(int i=a;i<=b;i++)
#define repp(i,a,b) for(int i=a;i>=b;i--)
#define vi vector<lli>
#define vvi vector<vi>
#define vpi vector<pair<lli,lli>>
#define pi pair<lli,lli>
#define msi multiset<lli>
#define mspi multiset<pair<lli,lli>>
#define mii map<lli,lli>
#define mpi map<pair<lli,lli>,lli>
#define si set<lli>
#define spi set<pair<lli,lli>>
#define qi queue<lli>
#define pqi priority_queue<lli>
#define pqimin priority_queue<lli,vi,greater<lli>>
#define geti(n) lli n; cin>>n;
#define get2i(n,m) lli n,m; cin>>n>>m;
#define get3i(n,m,k) lli n,m,k; cin>>n>>m>>k;
#define getvi(v,n) vi v(n); for(lli i=0;i<n;i++) cin>>v[i];
#define getvvi(v,n,m) vvi v(n,vi(m)); for(lli i=0;i<n;i++) for(lli j=0;j<m;j++) cin>>v[i][j];
#define getvpi(v,n) vpi v(n); for(lli i=0;i<n;i++) cin>>v[i].first>>v[i].second;
#define getpi (p) pi p; cin>>p.first>>p.second;
#define getmii(m,n) mii m; for(lli i=0;i<n;i++) { lli a,b; cin>>a>>b; m[a]=b; }
#define getstr(s) string s; cin>>s;
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<class T1, class T2> using ordered_map = tree<T1, T2, less<T1>, rb_tree_tag, tree_order_statistics_node_update>;
void print(lli n) { cout << n << "\n"; }
void print(lli n, lli m) { cout << n << " " << m << "\n"; }
void print(lli n, lli m, lli k) { cout << n << " " << m << " " << k << "\n"; }
void print(vi v) { for (auto i : v) cout << i << " "; cout << "\n"; }
void print(vvi v) { for (auto i : v) { for (auto j : i) cout << j << " "; cout << "\n"; } }
void print(string s) { cout << s << "\n"; }

const lli MOD = 1e9 + 7;

struct mi {
    int v;
    explicit operator int() const { return v; }
    mi() { v = 0; }
    mi(long long _v) : v(_v % MOD) { v += (v < 0) * MOD; }
};
mi &operator+=(mi &a, mi b) {
    if ((a.v += b.v) >= MOD) a.v -= MOD;
    return a;
}
mi &operator-=(mi &a, mi b) {
    if ((a.v -= b.v) < 0) a.v += MOD;
    return a;
}
mi operator+(mi a, mi b) { return a += b; }
mi operator-(mi a, mi b) { return a -= b; }
mi operator*(mi a, mi b) { return mi((long long)a.v * b.v); }
mi &operator*=(mi &a, mi b) { return a = a * b; }
mi pow(mi a, long long p) {
    assert(p >= 0);
    return p == 0 ? 1 : pow(a * a, p / 2) * (p & 1 ? a : 1);
}
mi inv(mi a) {
    assert(a.v != 0);
    return pow(a, MOD - 2);
}
mi operator/(mi a, mi b) { return a * inv(b); }

struct manacher{
    vector<int> p;

    void run_manacher(string s){
        int n = s.size();
        p.assign(n,1);
        int l = 1, r = 1;
        rep(i,1,n-1){
            p[i] = max(0, min(p[l+r-i], r-i));
            while(i+p[i] < n && i-p[i] >= 0 && s[i+p[i]] == s[i-p[i]]){
                p[i]++;
            }
            if(i+p[i]>r){
                l = i-p[i];
                r = i+p[i];
            }
        }
    }
    void build(string s){
        string t;
        for(auto v: s){
            t += "#";
            t += v;
        }
        run_manacher(t+"#");
    }

    int getlongest_palindrome(int centre, bool odd){
        int pos = 2*centre+1+(!odd);
        return p[pos]-1;
    }

    bool checkpalindrome(int l, int r){
        if((r-l+1) <= getlongest_palindrome((l+r)/2, (r-l+1)%2)){
            return true;
        }
        return false;
    }
};



vi complete_subset_graphs(vi adj){ 
    // adj[i] = 1 << j if i is connected to j
    // n<=20
    lli n = adj.size();
    vi dp(1ll<<n,0);
    rep(mask,0,(1<<n)-1){
        bool complete = true;
        rep(i,0,n-1){
            if((mask & (1ll<<i))){
                if(((adj[i] | (1ll<<i))&mask) != mask){
                    complete = false;
                    break;
                }
            }
        }
        if(complete) dp[mask] = 1;
    }
    return dp;
}

vi subsets_of_mask(lli mask){
    vi subsets;
    for(lli submask = mask; submask != 0; submask = (submask-1)&mask){
        //lli subset = mask^submask;
        // subset is a subset of mask
        // {submask} = {mask} - {subset}
        // tc 3^N
        subsets.pb(submask);
    }
    return subsets;
}

vpi prm_fact(lli a) {
    vpi res;
    for (lli i = 2; i * i <= a; ++i) {
        if (a % i == 0) {
            int cnt = 0;
            while (a % i == 0) {
                a /= i;
                cnt++;
            }
            res.pb({i, cnt});
        }
    }
    if (a > 1) res.pb({a, 1});
    return res;
}


lli solver(vpi& st){
    msi m1,m2;
    lli n = st.size();
    rep(i,0,n-1){
        lli x = st[i].first;
        lli y = st[i].second;

        if(m1.empty() || x < *m1.rbegin()){
            m1.insert(x);
        }
        else{
            m2.insert(x);
        }
        if(m1.empty() || y < *m1.rbegin()){
            m1.insert(y);
        }
        else{
            m2.insert(y);
        }

        while(m1.size() > m2.size() + 1){
            lli pusher = *m1.rbegin();
            m1.erase(m1.find(pusher));
            m2.insert(pusher);
        }
        while(m2.size() > m1.size()){
            lli pusher = *m2.begin();
            m2.erase(m2.find(pusher));
            m1.insert(pusher);
        }
    }

    lli med = *m1.rbegin();
    lli ans = 0;
    rep(i,0,n-1){
        ans += abs(med - st[i].first) + abs(med - st[i].second);
    }
    return ans;
}

void solve() {
    lli n,k;
    cin>>k>>n;

    vpi st;
    lli ans = 0;
    vector<array<lli,4>> sorter;
    rep(i,0,n-1){
        char start,end;
        lli a,b;
        cin>>start>>a>>end>>b;
        if(start == end)ans += abs(b-a);
        else {
            st.push_back({a,b});
            array<lli,4> arr = {a+b,i,a,b};
            sorter.push_back(arr);
        }
    }

    sort(all(sorter));
    if(k==1){
        ans += solver(st) + st.size();
    }
    else{
        st.clear();
        rep(i,0,(sorter.size()-1)/2){
            st.pb({sorter[i][2], sorter[i][3]});
        }
        ans += solver(st) + st.size();
        st.clear();
        rep(i,(sorter.size()-1)/2 + 1,sorter.size()-1){
            st.pb({sorter[i][2], sorter[i][3]});
        }
        ans += solver(st) + st.size();
        st.clear();
    }
    cout<<ans<<"\n";
}
 
signed main() {
    IOS int t=1;
    while(t--)
        solve();
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 14 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37