제출 #1216241

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1216241		Dzadzo	Square or Rectangle? (NOI19_squarerect)	C++20	0 / 100	0 ms	328 KiB

squarerect

#include <bits/stdc++.h>
#include "squarerect.h"

#define ll long long
// #define int ll
#define pb push_back
#define S second
#define F first
#define pii pair<int,int>
#define vi vector<int>
#define vvi vector<vi>
#define vvvi vector<vvi>
#define vp vector<pii>
#define vvp vector<vp>
#define vb vector<bool>
#define vvb vector<vb>
#define INF INT_MAX
#define MOD 1000000007
#define MAXN 200000
using namespace std;

// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

// bool inside_shape(int x,int y){
//     cout<<x<<" "<<y<<'\n';
//     bool res;
//     cin>>res;
//     return res;
// }


int N;
bool ask(int x,int y){

    if (1<=x && x<=N && 1<=y && y<=N)return inside_shape(x,y);
    return false;
}

bool am_i_square(int n, int q) {
    N=n;
    int Rmax=0,Rmin=INF,Cmax=0,Cmin=INF;
    for (int i=20;i<=n;i+=20){
        for (int j=20;j<=n;j+=20){
            
            if (ask(i,j)){
                Rmax=max(Rmax,i);
                Cmax=max(Cmax,j);
                Cmin=min(Cmin,j);
                Rmin=min(Rmin,i);
            }
        }
    }
    if (!Rmax)return false;

    if (Rmax-Rmin != Cmax - Cmin)return false;



    int R=Rmax;
    for (int bit=4;bit>=0;bit--){
        if (R+(1<<bit) >= Rmax+20 )continue;

        if (ask(R+(1<<bit),Cmax))R+=(1<<bit);

    }
    int r=Rmin;
    for (int bit=4;bit>=0;bit--){
        if (r-(1<<bit) <= Rmin-20 )continue;

        if (ask(r-(1<<bit),Cmin))r-=(1<<bit);

    }

     int C=Cmax;
    for (int bit=4;bit>=0;bit--){
        if (C+(1<<bit) >= Cmax+20 )continue;

        if (ask(Rmax,C+(1<<bit)))C+=(1<<bit);

    }
    int c=Cmin;
    for (int bit=4;bit>=0;bit--){
        if (c-(1<<bit) <= Cmin-20 )continue;

        if (ask(Rmin,c-(1<<bit)))c-=(1<<bit);

    }





    return R-r == C-c;




}
/*
signed main() {
    ios::sync_with_stdio(NULL);cin.tie(0);cout.tie(0);
    int tt;
    cin>>tt;
    while (tt--){
        int n;
        cin>>n;
        int a[n+1];
        for (int i=1;i<=n;i++)cin>>a[i];
    }
}




*/

• Subtask 1: 0 / 14
• Subtask 2: 0 / 19
• Subtask 3: 0 / 18
• Subtask 4: 0 / 49