제출 #121616

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
121616		duality	Bitaro, who Leaps through Time (JOI19_timeleap)	C++11	4 / 100	353 ms	11320 KiB

timeleap

#define DEBUG 0

#include <bits/stdc++.h>
using namespace std;

#if DEBUG
// basic debugging macros
int __i__,__j__;
#define printLine(l) for(__i__=0;__i__<l;__i__++){cout<<"-";}cout<<endl
#define printLine2(l,c) for(__i__=0;__i__<l;__i__++){cout<<c;}cout<<endl
#define printVar(n) cout<<#n<<": "<<n<<endl
#define printArr(a,l) cout<<#a<<": ";for(__i__=0;__i__<l;__i__++){cout<<a[__i__]<<" ";}cout<<endl
#define print2dArr(a,r,c) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<a[__i__][__j__]<<" ";}cout<<endl;}
#define print2dArr2(a,r,c,l) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<setw(l)<<setfill(' ')<<a[__i__][__j__]<<" ";}cout<<endl;}

// advanced debugging class
// debug 1,2,'A',"test";
class _Debug {
    public:
        template<typename T>
        _Debug& operator,(T val) {
            cout << val << endl;
            return *this;
        }
};
#define debug _Debug(),
#else
#define printLine(l)
#define printLine2(l,c)
#define printVar(n)
#define printArr(a,l)
#define print2dArr(a,r,c)
#define print2dArr2(a,r,c,l)
#define debug
#endif

// define
#define MAX_VAL 999999999
#define MAX_VAL_2 999999999999999999LL
#define EPS 1e-6
#define mp make_pair
#define pb push_back

// typedef
typedef unsigned int UI;
typedef long long int LLI;
typedef unsigned long long int ULLI;
typedef unsigned short int US;
typedef pair<int,int> pii;
typedef pair<LLI,LLI> plli;
typedef vector<int> vi;
typedef vector<LLI> vlli;
typedef vector<pii> vpii;
typedef vector<plli> vplli;

// ---------- END OF TEMPLATE ----------

int L[300000],R[300000];
int T[300000],A[300000],B[300000],C[300000],D[300000];
int l[300000],r[300000];
LLI ans[300000];
struct func {
    LLI b,x1,x2;
    LLI b2,x3;
    int init() { b = x1 = 0,x2 = 1e12; b2 = 0,x3 = 1e12; }
    int apply(int l,int r) {
        if (x1 == x2) {
            if (b < l) b = l;
            else if (b > r) b2 += b-r,b = r;
        }
        else {
            if (l > b+x2-x1) x1 = x2 = 0,b = l;
            else if (l > b) x1 += l-b,b = l;
            if (r < b) {
                b2 += b-r,x3 = x1;
                x1 = x2 = 0,b = r;
            }
            else if (r < b+x2-x1) x2 = x3 = x2-(b+x2-x1-r);
        }
        return 0;
    }
    plli eval(int x) {
        LLI p,q;
        if (x < x1) p = b;
        else if (x < x2) p = b+x-x1;
        else p = b+x2-x1;
        if (x < x3) q = b2;
        else q = b2+x-x3;
        return mp(p,q);
    }
};

int main() {
    int i,j;
    int N,Q;
    scanf("%d %d",&N,&Q);
    for (i = 0; i < N-1; i++) scanf("%d %d",&L[i],&R[i]);
    for (i = 0; i < Q; i++) {
        scanf("%d",&T[i]);
        if (T[i] == 1) scanf("%d %d %d",&A[i],&B[i],&C[i]),A[i]--,ans[i] = -1;
        else scanf("%d %d %d %d",&A[i],&B[i],&C[i],&D[i]),A[i]--,C[i]--;
    }

    int rr;
    for (rr = 0; rr < 2; rr++) {
        for (i = 0; i < N-1; i++) l[i] = L[i]-i,r[i] = R[i]-i-1;
        if (N*Q <= 1e6) {
            for (i = 0; i < Q; i++) {
                if (T[i] == 1) l[A[i]] = B[i]-A[i],r[A[i]] = C[i]-A[i]-1;
                else if ((T[i] == 2) && (A[i] <= C[i])) {
                    func f;
                    f.init();
                    for (j = A[i]; j < C[i]; j++) f.apply(l[j],r[j]);
                    plli p = f.eval(B[i]-A[i]);
                    if (p.first > D[i]-C[i]) p.second += p.first-(D[i]-C[i]);
                    ans[i] = p.second;
                }
            }
        }
        reverse(L,L+N-1),reverse(R,R+N-1);
        for (i = 0; i < Q; i++) {
            if (T[i] == 1) A[i] = N-2-A[i];
            else if (T[i] == 2) A[i] = N-1-A[i],C[i] = N-1-C[i];
        }
    }
    for (i = 0; i < Q; i++) {
        if (ans[i] != -1) printf("%lld\n",ans[i]);
    }

    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

timeleap.cpp: In member function 'int func::init()':
timeleap.cpp:65:58: warning: no return statement in function returning non-void [-Wreturn-type]
     int init() { b = x1 = 0,x2 = 1e12; b2 = 0,x3 = 1e12; }
                                                          ^
timeleap.cpp: In function 'int main()':
timeleap.cpp:96:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d",&N,&Q);
     ~~~~~^~~~~~~~~~~~~~~
timeleap.cpp:97:36: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     for (i = 0; i < N-1; i++) scanf("%d %d",&L[i],&R[i]);
                               ~~~~~^~~~~~~~~~~~~~~~~~~~~
timeleap.cpp:99:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d",&T[i]);
         ~~~~~^~~~~~~~~~~~
timeleap.cpp:100:66: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         if (T[i] == 1) scanf("%d %d %d",&A[i],&B[i],&C[i]),A[i]--,ans[i] = -1;
                        ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~
timeleap.cpp:101:65: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         else scanf("%d %d %d %d",&A[i],&B[i],&C[i],&D[i]),A[i]--,C[i]--;
              ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~

• Subtask 1: 4 / 4
• Subtask 2: 0 / 30
• Subtask 3: 0 / 66