Submission #1210939

#	Time	Username	Problem	Language	Result	Execution time	Memory
1210939		vanea	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++20	0 / 100	1175 ms	76188 KiB

sortbooks

#include <bits/stdc++.h>
using namespace std;
using ll = long long;

const int mxN = 4e6+10;

array<int, 2> st[mxN];
int lazy[mxN];

void build(int node, int l, int r, vector<int> &v) {
    if(l == r) {
        st[node] = {v[l], 0};
        return ;
    }
    int mid = (l+r)/2;
    build(node*2, l, mid, v);
    build(node*2+1, mid+1, r, v);
    st[node][0] = max(st[node*2][0], st[node*2+1][0]);
}

void push(int node, int l, int r) {
    if(lazy[node] == 0) return;
    if(l == r) return;
    lazy[node*2] = max(lazy[node*2], lazy[node]);
    st[node*2][1] = st[node*2][0]+lazy[node*2];
    lazy[node*2+1] = max(lazy[node*2+1], lazy[node]);
    st[node*2+1][1] = st[node*2+1][0]+lazy[node*2+1];
    lazy[node] = 0;
}

void upd(int node, int l, int r, int l1, int r1, int val) {
    push(node, l, r);
    if(l1 <= l && r <= r1) {
        st[node][1] = st[node][0]+val;
        lazy[node] = val;
        return ;
    }
    if(l1 > r || r1 < l) return ;
    int mid = (l+r)/2;
    upd(node*2, l, mid, l1, r1, val);
    upd(node*2+1, mid+1, r, l1, r1, val);
    st[node][1] = max(st[node*2][1], st[node*2+1][1]);
}

int qry(int node, int l, int r, int l1, int r1) {
    if(l1 <= l && r <= r1) return st[node][1];
    if(l1 > r || r1 < l) return -1;
    int mid = (l+r)/2;
    return max(qry(node*2, l, mid, l1, r1),
               qry(node*2+1, mid+1, r, l1, r1));
}

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    int n, q;
    cin >> n >> q;
    vector<int> v(n);
    for(int i = 0; i < n; i++) {
        cin >> v[i];
    }
    build(1, 0, n-1, v);
    stack<int> s;
    vector<bool> ans(q);
    vector<vector<array<int, 3>>> queries(n);
    for(int i = 0; i < q; i++) {
        int l, r, k;
        cin >> l >> r >> k; --l; --r;
        queries[l].push_back({r, k, i});
    }
    for(int l = n-1; l >= 0; l--) {
        while(!s.empty() && v[s.top()] < v[l]) s.pop();
        int b = s.empty() ? n : s.top();
        s.push(l);
        upd(1, 0, n-1, l+1, b-1, v[l]);
        for(auto [r, k, i] : queries[l]) {
            ans[i] = qry(1, 0, n-1, l, r) <= k;
        }
    }
    for(int i = 0; i < q; i++) {
        cout << ans[i] << '\n';
    }
    return 0;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 9
• Subtask 3: 0 / 13
• Subtask 4: 0 / 17
• Subtask 5: 0 / 30
• Subtask 6: 0 / 23