Submission #1208111

#TimeUsernameProblemLanguageResultExecution timeMemory
1208111gatapdevK blocks (IZhO14_blocks)C++20
0 / 100
0 ms328 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; const ll INF = LLONG_MAX / 4; // Segment tree supporting range-add and range-min queries typedef long long T; struct SegTree { int n; vector<T> st, lazy; SegTree(int _n) : n(_n), st(4*n, INF), lazy(4*n, 0) {} void apply(int p, int l, int r, T v) { st[p] += v; lazy[p] += v; } void push(int p, int l, int r) { if (lazy[p] != 0) { int m = (l+r)/2; apply(p<<1, l, m, lazy[p]); apply(p<<1|1, m+1, r, lazy[p]); lazy[p] = 0; } } void pull(int p) { st[p] = min(st[p<<1], st[p<<1|1]); } void build(int p, int l, int r, const vector<T>& base) { if (l == r) { st[p] = base[l]; return; } int m = (l+r)/2; build(p<<1, l, m, base); build(p<<1|1, m+1, r, base); pull(p); } void range_add(int p, int l, int r, int i, int j, T v) { if (i > r || j < l) return; if (i <= l && r <= j) { apply(p, l, r, v); return; } push(p, l, r); int m = (l+r)/2; range_add(p<<1, l, m, i, j, v); range_add(p<<1|1, m+1, r, i, j, v); pull(p); } T range_min(int p, int l, int r, int i, int j) { if (i > r || j < l) return INF; if (i <= l && r <= j) return st[p]; push(p, l, r); int m = (l+r)/2; return min(range_min(p<<1, l, m, i, j), range_min(p<<1|1, m+1, r, i, j)); } }; int main() { ios::sync_with_stdio(false); cin.tie(NULL); int n, K; cin >> n >> K; vector<ll> a(n+1); for (int i = 1; i <= n; i++) cin >> a[i]; // dp_prev for k-1, dp_cur for k vector<ll> dp_prev(n+1, INF), dp_cur(n+1, INF); dp_prev[0] = 0; // base case k=1: prefix max for (int i = 1; i <= n; i++) { dp_prev[i] = max(dp_prev[i-1], a[i]); } for (int k = 2; k <= K; k++) { SegTree st(n+1); st.build(1, 0, n, dp_prev); vector<int> stk; vector<int> left(n+1); stk.clear(); fill(dp_cur.begin(), dp_cur.end(), INF); for (int i = k; i <= n; i++) { // add a[i] to all j < i st.range_add(1, 0, n, 0, i-1, a[i]); int L = i; // maintain decreasing stack, rollback old maxima while (!stk.empty() && a[stk.back()] <= a[i]) { int t = stk.back(); stk.pop_back(); int lt = left[t]; // subtract old a[t] from [lt-1..t-1] st.range_add(1, 0, n, lt-1, t-1, -a[t]); L = lt; } stk.push_back(i); left[i] = L; // query dp for segment ending at i dp_cur[i] = st.range_min(1, 0, n, k-1, i-1); } dp_prev.swap(dp_cur); } cout << dp_prev[n]; return 0; }
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