제출 #1207540

#제출 시각아이디문제언어결과실행 시간메모리
1207540abczzFish 2 (JOI22_fish2)C++20
25 / 100
4103 ms302088 KiB
#include <iostream> #include <map> #include <array> #include <algorithm> #include <cmath> #define ll long long using namespace std; ll n, q, ty, x, y, A[100000], X[100000], ps[100000]; map <ll, ll> mp[30]; struct BIT{ ll bt[100001]; void add(ll id, ll w) { ++id; while (id <= n) { bt[id] += w; id += id & -id; } } ll ask(ll id) { ll res = 0; while (id) { res += bt[id]; id -= id & -id; } return res; } ll query(ll l, ll r) { if (l > r) return (ll)1e18; return ask(r+1) - ask(l); } }bit; array<ll, 2> operator+(array<ll, 2> a, array<ll, 2> b) { return {a[0] + b[0], a[1] + b[1]}; } struct SegTree{ array<ll, 2> st[400000]; void update(ll id, ll l, ll r, ll q, array<ll, 2> w) { if (l == r) { st[id] = w; return; } ll mid = (l+r)/2; if (q <= mid) update(id*2, l, mid, q, w); else update(id*2+1, mid+1, r, q, w); st[id] = st[id*2] + st[id*2+1]; } array<ll, 2> query(ll id, ll l, ll r, ll ql, ll qr) { if (qr < l || r < ql) return {0, 0}; else if (ql <= l && r <= qr) return st[id]; ll mid = (l+r)/2; return query(id*2, l, mid, ql, qr) + query(id*2+1, mid+1, r, ql, qr); } }ST[30]; ll check(ll j, ll u, ll xl, ll xr) { ll ql = u, qr = u, v = 1e18; auto it = mp[j].find(u); if (it != mp[j].begin()) { auto pv = prev(it); ql = pv->first+1; if (pv->first >= xl) v = min(v, A[pv->first]); } else ql = 0; auto nx = next(it); if (nx != mp[j].end()) { qr = nx->first-1; if (nx->first <= xr) v = min(v, A[nx->first]); } else qr = n-1; ql = max(ql, xl); qr = min(qr, xr); if (bit.query(ql, qr) < v && v != 1e18) return 1; else return 0; } void reconstruct(ll j, ll l, ll r) { ll ql = l, qr = r-1, v = A[r], tot = 0; if (j == X[l]-1) tot = check(j, l, (ll)-1e18, (ll)1e18); array <ll, 2> u = {0, 0}; if (j) u = ST[j-1].query(1, 0, n-1, l, r-1); if (bit.query(l+1, r-1) < min(A[l], A[r])) { ST[j].update(1, 0, n-1, l, {r-l-1-u[1]+tot, r-l-1+tot}); } else { ST[j].update(1, 0, n-1, l, {tot, u[1]+tot}); } } int main() { cin.tie(0); ios::sync_with_stdio(0); cin >> n; for (int i=0; i<n; ++i) { cin >> A[i]; bit.add(i, A[i]); ps[i] = A[i] + (i == 0 ? 0 : ps[i-1]); X[i] = (ll)(log2(A[i])); for (int j=0; j<X[i]; ++j) ++mp[j][i]; } for (int j=0; j<30; ++j) { auto it = mp[j].begin(); while (it != mp[j].end()) { auto nx = next(it); if (nx == mp[j].end()) break; reconstruct(j, it->first, nx->first); it = nx; } } cin >> q; while (q--) { cin >> ty >> x >> y; if (ty == 1) { --x; ll z1 = X[x], z2 = (ll)log2(y); bit.add(x, y-A[x]); A[x] = y, X[x] = z2; for (int j=0; j<30; ++j) { ST[j].update(1, 0, n-1, x, {0, 0}); if (j >= z1 && j < z2) ++mp[j][x]; if (j >= z2 && j < z1) mp[j].erase(x); auto it = mp[j].lower_bound(x); if (it != mp[j].end()) { if (it != mp[j].begin()) { auto pv = prev(it); reconstruct(j, pv->first, it->first); } if (it->first == x) { auto nx = next(it); if (nx != mp[j].end()) { reconstruct(j, it->first, nx->first); if (X[nx->first]-1 == j) { auto nx2 = next(nx); if (nx2 != mp[j].end()) reconstruct(j, nx->first, nx2->first); } } } else if (X[it->first]-1 == j) { auto nx2 = next(it); if (nx2 != mp[j].end()) reconstruct(j, it->first, nx2->first); } } else if (it != mp[j].begin()) { auto pv = prev(it); ST[j].update(1, 0, n-1, pv->first, {0, 0}); } } } else { --x, --y; ll f = y-x+1, nx = x, ny = y; for (int j=0; j<30; ++j) { auto it = mp[j].lower_bound(x); if (it == mp[j].end() || it->first > y) continue; auto it2 = mp[j].lower_bound(y+1); if (it2 == mp[j].begin()) continue; it2 = prev(it2); //cout << j << " " << it->first << " " << it2->first << endl; if (bit.query(x, it->first-1) < A[it->first]) nx = it->first; if (bit.query(it2->first+1, y) < A[it2->first]) ny = it2->first; } f -= nx-x+y-ny; //cout << f << " " << nx << " " << ny << endl; for (int j=0; j<30; ++j) { auto it = mp[j].lower_bound(nx); if (it == mp[j].end() || it->first > ny) continue; auto it2 = mp[j].lower_bound(ny+1); if (it2 == mp[j].begin()) continue; it2 = prev(it2); //cout << j << " " << it->first << " " << it2->first << endl; if (it->first != it2->first) { auto u = ST[j].query(1, 0, n-1, it->first, it2->first-1); if (X[it->first]-1 == j) u[0] += check(j, it->first, x, y) - check(j, it->first, (ll)-1e18, (ll)1e18); f -= u[0]; } if (X[it2->first]-1 == j) { f -= check(j, it2->first, x, y); } } cout << f << '\n'; } } }
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