제출 #1203204

#제출 시각아이디문제언어결과실행 시간메모리
1203204SpyrosAlivRectangles (IOI19_rect)C++20
0 / 100
93 ms34372 KiB
#include <bits/stdc++.h> using namespace std; #define ll long long vector<pair<int, int>> delta = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; vector<vector<int>> g; int n, m; vector<vector<bool>> vis; int u, d, l, r, sz; bool inside(int i, int j) { return i >= 0 && i < n && j >= 0 && j < m; } void dfs(int i, int j) { if (!inside(i, j) || g[i][j] || vis[i][j]) return; vis[i][j] = true; sz++; u = min(u, i); d = max(d, i); l = min(l, j); r = max(r, j); for (auto [di, dj]: delta) { dfs(i + di, j + dj); } } ll count_rectangles(vector<vector<int>> G) { g = G; n = g.size(); m = g[0].size(); vis.assign(n, vector<bool>(m, false)); ll ans = 0; for (int i = 1; i < n-1; i++) { for (int j = 1; j < m-1; j++) { u = n; d = 0; l = m; r = 0; sz = 0; if (!vis[i][j] && g[i][j] == 0) { dfs(i, j); } if (u == 0 || d == n || l == 0 || r == m) continue; if ((abs(u - d) + 1) * (r - l + 1) == (r - l + 1) * (abs(u - d) + 1) && (abs(u - d) + 1) * (r - l + 1) == sz) { ans++; } } } return ans; }
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