Submission #12032

#	Time	Username	Problem	Language	Result	Execution time	Memory
12032		gs14004	trapezoid (balkan11_trapezoid)	C++98	35 / 100	500 ms	6252 KiB

trapezoid

#include <cstdio>
#include <vector>
#include <algorithm>
using namespace std;

int n;
int a[100005], b[100005], c[100005], d[100005];
vector<int> vu, vd;
int dp[100005], cnt[100005];

int main(){
    scanf("%d",&n);
    for (int i=0; i<n; i++) {
        scanf("%d %d %d %d",&a[i],&b[i],&c[i],&d[i]);
        vu.push_back(a[i]);
        vu.push_back(b[i]);
        vd.push_back(c[i]);
        vd.push_back(d[i]);
    }
    sort(vu.begin(),vu.end());
    sort(vd.begin(),vd.end());
    for (int i=0; i<n; i++) {
        a[i] = (int)(lower_bound(vu.begin(),vu.end(),a[i]) - vu.begin());
        b[i] = (int)(lower_bound(vu.begin(),vu.end(),b[i]) - vu.begin());
        c[i] = (int)(lower_bound(vd.begin(),vd.end(),c[i]) - vd.begin());
        d[i] = (int)(lower_bound(vd.begin(),vd.end(),d[i]) - vd.begin());
    }
    for (int i=0; i<n; i++) {
        dp[i] = 1;
        for (int j=0; j<n; j++) {
            if(b[j] < a[i] && d[j] < c[i]){
                dp[i] = max(dp[i],dp[j]+1);
            }
        }
        for (int j=0; j<n; j++) {
            if(dp[j] && dp[j] + 1 == dp[i] && b[j] < a[i] && d[j] < c[i]){
                cnt[i] += cnt[j];
                cnt[i] %= 30013;
            }
        }
        if(dp[i] == 1) cnt[i] = 1;
    }
    int mcnt = *max_element(dp,dp+n);
    int rcnt = 0;
    for (int i=0; i<n; i++) {
        if(dp[i] == mcnt){
            rcnt += cnt[i];
            rcnt %= 30013;
        }
    }
    printf("%d %d",mcnt,rcnt);
}

Compilation message (stderr)

trapezoid.cpp: In function 'int main()':
trapezoid.cpp:12:19: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d",&n);
                   ^
trapezoid.cpp:14:53: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d %d %d %d",&a[i],&b[i],&c[i],&d[i]);
                                                     ^

• Subtask 1: 35 / 100