Submission #1202902

#	Time	Username	Problem	Language	Result	Execution time	Memory
1202902		zeta7532	Magic Show (APIO24_show)	C++20	0 / 100	2 ms	368 KiB

Alice

#include <bits/stdc++.h>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
using namespace std;
using ll = long long;
const ll mod = 998244353;
#define fi first
#define se second
#define rep(i,N) for(ll i=0;i<N;i++)
#define all(A) A.begin(),A.end()
#define faster ios::sync_with_stdio(false);cin.tie(nullptr)
#include <vector>
#include "Alice.h"

// you may define some global variables, but it does not work if you try to transfer any information from function Alice() to function Bob() through these variables.
// you had better not use the same global variables in function Alice() and in function Bob().

std::vector<std::pair<int,int>> Alice(){
	// add your code here
	
	// change below into your code
    ll N=5000;
    ll X=setN(N);
    X--;
    vector<ll> x(60);
    rep(i,60){
        x[i]=X%2;
        X/=2;
    }
    vector<pair<int,int>> ans;
    rep(i,60){
        ans.push_back({4999,i*2});
        ans.push_back({4999,i*2+1});
    }
    for(ll i=120;i<4999;i++){
        ll j=i%60;
        ll k=j*2+x[j];
        ans.push_back({k,i});
    }
    rep(i,N-1) ans[i].fi++,ans[i].se++;
    return ans;
}

Bob

#include <bits/stdc++.h>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
using namespace std;
using ll = long long;
const ll mod = 998244353;
#define fi first
#define se second
#define rep(i,N) for(ll i=0;i<N;i++)
#define all(A) A.begin(),A.end()
#define faster ios::sync_with_stdio(false);cin.tie(nullptr)
#include <vector>
#include "Bob.h"

// you may define some global variables, but it does not work if you try to transfer any information from function Alice() to function Bob() through these variables.
// you had better not use the same global variables in function Alice() and in function Bob().

long long Bob(std::vector<std::pair<int,int>> V){
	// add your code here
	
    ll N=5000;
    vector<ll> deg(N,0);
    ll M=V.size();
    rep(i,M){
        deg[V[i].fi-1]++;
        deg[V[i].se-1]++;
    }
    ll ans=0;
    ll bit=1;
    rep(i,60){
        if(deg[i*2]<deg[i*2+1]) ans+=bit;
        bit*=2;
    }
    return ans+1; // change this into your code
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 30
• Subtask 3: 0 / 65