/*
I:
1. The path does not conatin layers.
Must compute:
1. the number of cells in the territory.
======================
======================
*/
#include "hexagon.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define vi vector<int>
#define pi pair<int,int>
#define pb push_back
#define sz(x) ((int)x.size())
#define sp ' '
#define endl "\n"
#define all(x) (x).begin(),(x).end()
#define rep(i,x,n) for(int i=x; i<=n; ++i)
#define For(i,n) rep(i,0,n-1)
#define ff first
#define ss second
#define ld long double
#define mp make_pair
const ll mxN=6e5+10,OO=2e9,mod=1e9+7;
const int dx[]{0,0,-1,1}, dy[]{1,-1,0,0};
void cmn(int &a,int b){a = min(a,b);}
void cmx(int &a,int b){a = max(a,b);}
int draw_territory(int N, int A, int B,vector<int> D, vector<int> L){
ll v=L.back(),ans=v+1;
ans = v * (v+1)/2; ans %= mod;
if(N==3){
assert(L[0]==L[1]&&L[1]==L[2]);
}
return ans;
}
